Question

The specific heat of ice is 0.5 calories/gram°C. 20 grams of ice will require _____ calories to raise the temperature 1°C. 0.5 1.0 5.0 10

Answer 1

Answer:

10 calories

Explanation:

The thermal energy needed to increase the temperature of a substance is given by

$Q=m C \Delta T$

where

m is the mass of the substance

C is the specific heat of the substance

$\Delta T$ is the increase in temperature

In this problem, the mass of the ice is m=20 g, the specific heat is C=0.5 calories/gram°C, and the increase in temperature is $\Delta T=1^{\circ}$. Therefore, the energy required is

$Q=(20 g)(0.5 cal/g^{\circ}C)(1^{\circ}C)=10 cal$

Answer 2

0.5 x 20 = 10
The answer is 10.