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3 years ago

Which of the following refers to the process of hydrolysis?

2 answers:

5 0

The statement that refers to the process of hydrolysis is Water is needed for hydrolysis to take place. The answer is letter C. The rest of the statements do not answer the question above.

tiny-mole [99]3 years ago

3 0

Answer:

The answer is: C.) Water is needed for hydrolysis to take place.

Explanation:

Hydrolysis is the process where a molecule of water react with another molecule and its result is the division of the molecule of water. The atoms of the molecule of water become part of other structures before the separation. Taking this into account, answer A is wrong, because there is no released of water, answer B is also wrong because the result is not neccesarily a chain of molecules, answer D is not true because it no referes to a process that involves plants and animals. Answer C is correct.

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A mole of cars stacked end to end would stretch back and forth across the United States how many times? Measured length of 1 car

vekshin1

Answer:

i am potato

Explanation:

4444141+5-45458/85*55474

3 0

3 years ago

The isomerization of methylisonitrile to acetonitrileCH3NC(g)→CH3CN(g)is first order in CH3NC . The rate constant for the reacti

lisabon 2012 [21]

Answer:

Option E, Half life = $2.96\times 10^3\ s$

Explanation:

For a first order reaction, rate constant and half-life is related as:

$t_{1/2}=\frac{0.693}{k}$

Where,

$t_{1/2}$ = Half life

k = Rate constant

Rate constant given = $2.34\times 10^{-4}\ s^{-1}$

$t_{1/2}=\frac{0.693}{k}$

$=\frac{0.693}{2.34 \times 10^{-4}}=2.96\times 10^3\ s$

So, the correct option is option E.

4 0

4 years ago

What orbitals are used to form the 10 sigma bonds in propane (ch3ch2ch3)? Label each atom with the appropriate hybridization. Dr

SVETLANKA909090 [29]

Mixing of pure orbitals having nearly equal energy to form equal number of completely new orbitals is said to be hybridization.

For the compound, $CH_3CH_2CH_3$ the electronic configuration of the atoms, carbon and hydrogen are:

Carbon (atomic number=6): In ground state= $1s^{2}2s^{2}2p^{2}$

In excited state: $1s^{2}2s^{1}2p^{3}$

Hydrogen (atomic number=1): $1s^{1}$

All the bonds in the compound is single bond( $\sigma$ -bond) that is they are formed by head on collision of the orbitals.

The structure of the compound is shown in the image.

The Carbon-Hydrogen bond is formed by overlapping of s-orbital of hydrogen to p-orbital of carbon.

In order to complete the octet the required number of electrons for carbon is 4 and for hydrogen is 1. So, the electron in $1s^{1}$ of hydrogen will overlap to the 2p^{3}-orbital of carbon.

Thus, the hybridization of Hydrogen is $s$ -hybridization and the hybridization of Carbon is $sp^{3}$ -hybridization.