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Fynjy0 [20]
3 years ago
5

Which option describes nonmetals?

Chemistry
2 answers:
Anastasy [175]3 years ago
8 0

Nonmetals are moldable and easily shaped.

Kipish [7]3 years ago
3 0

Nonmetals can be described as non conductors

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The volume of an aluminum sample is 251 to the power of 3 what is the mass of the sample?
timurjin [86]
15813251 because when you use exponents you have to multiply that number over and over again to the amount that the exponents worth
8 0
3 years ago
How many liters will 10.0 grams of hydrogen occupy at stp​
Dmitrij [34]

Answer:

38.36 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of H₂ in atm (P = 1.0 atm, STP conditions).

V is the volume of H₂ in L (V = ??? L).

n is the no. of moles of H₂ in mol (n = mass/molar mass = (10.0 g)/(2.0 g/mol) = 5.0 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of H₂ in K (T = 0.0°C + 273 = 273.0 K, STP conditions).

<em>∴ V = nRT/P</em> = (5.0 mol)(0.0821 L.atm/mol.K)(273.0 K)/(1.0 atm) = <em>38.36 L.</em>

4 0
3 years ago
How does electronegativity change going down and across the periodic table?
postnew [5]

Answer:

On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.

Explanation:

8 0
2 years ago
Read 2 more answers
galvanic cell is powered by the following redox reaction: (g) (aq) (l)(aq) (s) (aq) Answer the following questions about this ce
kotykmax [81]

Answer:

Explanation:

1. the 1/2 reaction that occurs at the cathode

3Cl2(g) +6e^- -------------> 6Cl^- (aq)

2 the 1/2 reaction that occurs at the anode

2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-      

2MnO2(s) + 8OH^-(aq) ----------> 2MnO4^- (aq) + 4H2O(l) +6e^-

E0 = -0.59v

3Cl2(g) +6e^- -------------> 6Cl^- (aq)                                                  

E0 = 1.39v

3Cl2 (g) + 2MnO2 (s) + 8OH^(−) (aq)---------> 6Cl^(−) (aq) + 2MnO4^(−) (aq) + 4H2O (l)  

E0cell = 0.80v

5 0
3 years ago
Thorium-234 has a half-life of 24.1 days. How much of a 100-g sample of thorium-234 will be unchanged after 48.2 days?
oee [108]
Half-life means that the matter degrades by 50% at each interval. 48.2 days is 2 intervals.

So, it would go down by 50% in the first interval, making it 50g. Then it would go down by another 50% from there, making the final amount of undecayed thorium-234 25g.
7 0
3 years ago
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