In order to convert mm³ to m³, we use the conversion factor of 1m = 1000 mm. Also, the conversion factor of mm³ to cm³, we use the factor of 1cm = 10 mm.
= (0.45 mm³) x (1 m/ 1000 mm)³ = 4.5 x 10^-10 m³
= (0.45 mm³) x (1 cm/10 mm)³ = 4.5 x 10^-4 cm³
Thus, the answer is letter B.
When a mixture of 10 moles of SO2 and 15 moles of O2 was passed over a catalyst, 10 moles of SO3 was formed.
Answer:
B) Add appropriate quantities of weak acid and its conjugate base to water.
C) Partially neutralize a weak acid solution by addition of a strong base.
(D) Partially neutralize a weak base solution by addition of a strong acid.
Explanation:
A buffer solution is made by a weak acid and its conjugated base or a weak base and its conjugated acid.
If you add a weak acid to water, you can adjust the pH of the buffer solution by adding a strong base.
If ypu add a weak base to water, you can adjust the pH of the buffer solution by adding a strong acid.
Answer:
V = 5.17L
Explanation:
Mass of gas = 8.7g
T = 23°C = (23 + 273.15)K = 296.15K
P = 1.15 atm
V = ?
R = 0.082atm.L / mol.K
From ideal gas equation
PV = nRT
P = pressure of the gas
V = volume of the gas
n = no. Of moles
R = ideal gas constant
T = temperature of the gas
no of moles = mass / molar mass
Molar mass of Chlorine = 35.5g / mol
No. Of moles = 8.7 / 35.5
No. Of moles = 0.245 moles
PV = nRT
V = nRT / P
V = (0.245 * 0.082 * 296.15) / 1.15
V = 5.9496 / 1.15
V = 5.17L
The volume of the gas is 5.17L
