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KengaRu [80]
3 years ago
10

1. Is this equation balanced? Explain your answer. Na + Cl2 → NaCl ?

Chemistry
2 answers:
Vlad1618 [11]3 years ago
7 0
No it is not balanced. The answer would be Na+Cl2=NaCl2 because it says l2
german3 years ago
6 0
No the question is not balanced
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Which of the following would the kinetic theory address?
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I think it’s B vibrations in molecules
Explanation: The Kinetic Theory of Matter states that matter is composed of a large number of small particles—individual atoms or molecules—that are in constant motion.
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The kinetic energy within molecules of an object _ when heat is added? Increases decreases or remains the same
kotegsom [21]

The kinetic energy of an object increases when heat is added.

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3 years ago
How many moles of aluminum oxide would form if 12.5 moles of aluminum burned​
jarptica [38.1K]
<h3>Al + O2 -> Al2O3</h3>

Balance it:

<h3>2Al + 3O2 -> 2Al2O3</h3><h3 />

So you need 2 Al and 3 O2 to make 2 Al2O3 (aluminum oxide).

I'm going to assume you have all the O2 you need.

Since 2 mols of Al is needed to make 2 mols of the product, it's a 1:1 ratio. You get as much aluminum oxide for as much aluminum you burn.

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7 0
3 years ago
the amount of heat involved in the synthesis of 1 mole of a compound from its elements with all substances in their standard sta
otez555 [7]

<span>The </span>standard enthalpy of formation<span> <span>is defined as the change in </span></span>enthalpy<span> <span>when one mole of a substance in the </span></span>standard<span> <span>state (1 atm of pressure and temperature of 298.15 K) is </span></span>formed<span> <span>from its pure elements under the same conditions.</span></span>

4 0
3 years ago
Read 2 more answers
Calculate the value of the diffusion coefficient D (in m2/s) at 547°C for the diffusion of some species in a metal; assume that
svetlana [45]

Answer : The value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

Explanation :

Formula used :

D=D_o\times \exp \left(-\frac{Q_d}{RT}\right )

where,

D = diffusion coefficient = ?

D_o = 5.6\times 10^{-5}m^2/s

Q_d = 177kJ/mol

R = gas constant = 8.314 J/mol.K

T = temperature = 547^oC=273+547=820K

Now put all the given values in the above formula, we get:

D=5.6\times 10^{-5}m^2/s\times \exp \left(-\frac{177kJ/mol}{(8.314J/mol.K)\times (820K)}\right )

D=2.97\times 10^{-16}m^2/s

Thus, the value of diffusion coefficient is, 2.97\times 10^{-16}m^2/s

6 0
3 years ago
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