Answer:
576
Step-by-step explanation:
W=1wh
Answer:
Option D. {7 + i√71 / 20, 7 – i√71 / 20}
Step-by-step explanation:
10m² – 7m + 3 = 0
Using formula method, the solution to equation can be obtained as follow:
10m² – 7m + 3 = 0
Coefficient of m² (a) = 10
Coefficient of –7m (b) = –7
Constant (c) = 3
m = –b ±√(b² – 4ac) / 2a
= – –7 ±√((–7)² – 4 × 10 × 3) / 2 × 10
= 7 ±√(49 – 120) / 20
= 7 ±√(–71) / 20
Recall:
–17 = –1 × 17
Thus,
7 ±√(–71) / 20 = 7 ±√(–1 × 71) / 20
Recall:
√–1 = i
Thus,
7 ±√(–1 × 71) / 20 = 7 ± i√71 / 20
= 7 + i√71 / 20 or 7 – i√71 / 20
Therefore, the solutions to the equation are:
{7 + i√71 / 20, 7 – i√71 / 20}
Answer:
Step-by-step explanation:
4 cos²q = 3
cos²q = 3/4
cosq = ½√3
q = 30°, 330° or π/6, 5π/6 radians
No map given but it shouldn't matter.
E is the 5th letter, L the 12th.
Start at S(6,12). End at E(10,5)
The vector between them, E-S=(4,-7)
Each unit is 1/16 of a mile, though that probably doesn't matter that much.
Doug has to stay on the grid, so has to run |4|+|7|=11 units. At 30 mi/hr that takes (11/16)/30 = 0.022916 hours.
Bert can go diagonally, so flies √(4²+7²)=√65 ≈ 8.06 units. At 20 mi/hr that takes (8.06/16)/20 = 0.025194 hours.
Answer: Doug wins
Why? Because it's quicker to cover 4+7 at 30 mph than it is to cover √(4²+7²) at 20 mph. That is, Doug is 1.5 times faster and the 1.5 times the diagonal distance is more than the grid distance.