Answer:
-5
Step-by-step explanation:
Moving all terms of the quadratic to one side, we have
.
A quadratic has one real solution when the discriminant is equal to 0. In a quadratic 
, the discriminant is 
.
(The discriminant is more commonly known as 
, but I changed the variable since we already have a 
in the quadratic given.)
In the quadratic above, we have 
, 
, and 
. Plugging this into the formula for the discriminant, we have
.
Using the distributive property to expand and simplifying, the expression becomes
Setting the discriminant equal to 0 gives
.
We can then solve the equation as usual: first, divide by 2 on both sides:
.
Squaring both sides gives
,
and subtracting 5 from both sides, we have
Answer:
-3. im taking this course right now so i know its correct, if you do the box method it comes out to -3.
Step-by-step explanation:
We have that
sin ∅=-0.7660
the sin ∅ is negative
so
∅ belong to the III or IV quadrant
but
180°< ∅ < 270°
hence
∅ belong to the III quadrant
sin ∅=-0.7660
sin² ∅+cos² ∅=1
cos² ∅=1-sin² ∅------> cos² ∅=1-(0.7660)²-----> 0.4132
cos ∅=√0.4132-----> cos ∅=0.6428
the value of cos ∅ is negative-------> III quadrant
cos ∅=-0.6428
tan ∅=sin ∅/ cos ∅----> tan ∅=-0.7660/-0.6428----> tan ∅=1.1917
the answer is
tan ∅ is 1.1917
The answer is D. THe last one.
Answer:
7
Step-by-step explanation:
g(x) = 3/2 x + 4
g(2) = 3/2 * 2 + 4
g(2) = 3 +4
g(2) = 7
