Explanation: IE1 increases from left to right across a period. However, since Na has only one valence electron, IE2 for Na involves the removal of a core electron − requiring significantly more energy.

7 0

3 years ago

A red sports drink contains Red 40 dye. A 5.4 mL aliquot of this sports drink was diluted to 25.0 mL with deionized water in a v

miskamm [114]

Answer:

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

Explanation:

Concentration of red dye in sport drink before dilution $C_1=?$

Volume of the sport drink before dilution $V_1=5.4 mL$

Concentration of red dye in sport drink after dilution $C_2=18.1 ppm$

Volume of the sport drink after dilution $V_2=25.0 mL$

$C_1V_1=C_2V_2$ ( dilution )

$C_1=\frac{C_2V_2}{V_1}=\frac{18.1 ppm\times 25.0 mL}{5.4 mL}$

$C_1=83.80 ppm\approx 84.0ppm$

84.0 ppm is the concentration of Red 40 dy in the original sports drink.

6 0

3 years ago

The speed of a wave in the string is 16.2ms. The mass per unit length of the string is 0.3ms calculate tension in the string

liberstina [14]

Answer:

The tension in the string is 78.73 N.

Explanation:

The tension in the string can be determined from the expression;

v = $\sqrt{\frac{T}{m} }$

where: v is the speed of the wave in the sting, T is the tension in the string and m is the mass per unit length of the sting.

Given that: v = 16.2 m/s, and m = 0.3 kg/m.

Then;

16.2 = $\sqrt{\frac{T}{0.3} }$

Square both sides to have,

$(16.2)^{2}$ = $\frac{T}{0.3}$

T = $(16.2)^{2}$ x 0.3

= 252.44 x 0.3

= 78.732

T = 78.732 N

The tension in the string is 78.73 N.

6 0

3 years ago