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vlabodo [156]
3 years ago
13

Percocet contains oxycodone at varying strengths.Every strength also contains 325 mg of

Chemistry
1 answer:
Marat540 [252]3 years ago
6 0
5.56 Rhats The right answer
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Water is placed in a graduated cylinder and the volume is recorded as 43.5 ml. a homogeneous sample of metal pellets with a mass
natulia [17]
Density = mass /volume of the body. mass = 10.88 g, volume of the liquid displaced= 49.4-43.5=5.9 ml.

density = 10.88/5.9=1.844 g/ml~1.84 g/ml

The volume displaced is exactly the same as that of the body (The Eureka fro Archimedes!)
7 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!
My name is Ann [436]

Answer: It's the anode broski (B)

Explanation: I'm taking the Chem summer course too broski, this was the correct answer. Cheers broski

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Que es la oms y porque a esta organizacion le preocupan temas como el expuesto
deff fn [24]

Answer:que es la oms y porque a esta organizacion le preocupan temas como el expuesto

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3 years ago
Compare the strength of intermolecular forces in no2 to the strength of intermolecular forces in n2
matrenka [14]
N2  is non-polar molecules,
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7 0
3 years ago
Read 2 more answers
A 0.67 gram sample of chromium is reacted with sulfur. The resulting chromium sulfide has a mass of 1.2888 grams. What is the em
spin [16.1K]

Answer:

Cr₂S₃

Explanation:

From the question given above, the following data were obtained:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Empirical formula =?

Next, we shall determine the mass of sulphur (S) in the compound. This can be obtained as follow:

Mass of chromium (Cr) = 0.67 g

Mass of chromium sulfide = 1.2888 g

Mass of sulphur (S) =?

Mass of S = (Mass of chromium sulfide) – (Mass of Cr)

Mass of S = 1.2888 – 0.67

Mass of S = 0.6188 g

Finally, we shall determine the empirical formula of the compound. This can be obtained as follow:

Mass of Cr = 0.67 g

Mass of S = 0.6188 g

Divide by their molar mass

Cr = 0.67 / 52 = 0.013

S = 0.6188 / 32 = 0.019

Divide by the smallest

Cr = 0.013 / 0.013 = 1

S = 0.019 / 0.013 = 1.46

Multiply by 2 to express in whole number

Cr = 1 × 2 = 2

S = 1.46 × 2 = 3

Therefore, the empirical formula of the compound is Cr₂S₃

5 0
3 years ago
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