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3 years ago

Calculate the molarity of 13.1 g of NaCl in 727 mL of solution

Chemistry

1 answer:

valentina_108 [34]3 years ago

5 0

Answer:

The molarity of the solution is 0,31 M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

13,1 g ---------x= (13,1 g x 1 mol NaCl)/58, 5 g= 0, 224 mol NaCl

727 ml solution------ 0, 224 mol NaCl

1000ml solution------x= (1000ml solutionx0, 224 mol NaCl)/727 ml solution

x=0,308 mol NaCl---> <em>The solution is 0,31 molar (0,31 M)</em>

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Answer:

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Explanation:

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Answer:

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3 years ago

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torisob [31]

Answer:

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Explanation:

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2 years ago

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3 years ago

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A balloon is inflated such that a radius is 7 cm what is the volume of air inside the balloon in milliliters

DedPeter [7]

Answer:

$V=14373.33\ \text{mm}^3$

Explanation:

It is given that,

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$V=\dfrac{4}{3}\pi r^3\\\\\text{Put r = 7 cm}\\\\V=\dfrac{4}{3}\times \dfrac{22}{7}\times 7\times 7\times 7\\\\V=1437.33\ \text{cm}^3\\\\\text{We know that, 1 cm = 10 mm}\\\\\text{So},\\\\V=14373.33\ \text{mm}^3$

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