Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:segment YZ ≈ 19.4 inangle X ≈ 85.3°angle Z ≈ 26.7°Explanation:1) Given two side lenghts and one angle you can use sine law:
2) Using the sides with length 43 in and 40in, and the corresponding opposite angles, Z and 68°, that leads to:
From which you can clear sinZ and get:
sinZ = 43 × sin(68) / 40 = 0.9967
⇒ Z = arcsine(0.9967) ≈ 85.36°
3) The third angle can be determined using 85.36° + 68° + X = 180°
⇒ X = 180° - 85.36° - 68° = 26.64°.
4) Finally, you can apply the law of sine to obtain the last missing length:
From which: x = 40 × sin(26.64°) / sin(68°) = 19.34 in
The answer, then is:
segment YZ ≈ 19.4 in
angle X ≈ 85.3°
angle Z ≈ 26.7°
Answer:
7.6
Step-by-step explanation:
m<DBA is 68 degrees
Hello,
-1<=cos x <=1
==>-10<=10*cos x <=10
max y=10 if x=0 +2kπ ==>x=0,-2π,2π
min y=-10 if x=π+2kπ ==>x=-π,π
~p~9 .............
Show work
9=p
