The midpoint would be (5,9)
The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Given a quadratic function for the transformations given the function f(x) = x²
If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value
- Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)
Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1
Learn more here: brainly.com/question/15381183
First, we'll find the slope of the new line. The first line has a slope of 
. Take the negative reciprocal of this (Flip the numerator and denominator, then multiply by 
) to get 
for the new slope.
Then, we'll use the point-slope form to make the new equation, where 
is the slope and 
is a point on the line:
C - 7.6 = -4
c = -4 + 7.6
c = 3.6
