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3 years ago

To rotate text in a cell select the option in the alignment grouping

2 answers:

8 0

To rotate cell data, follow these steps:<span>1.Select the cells you want to format.2.On the Home tab, in the Alignment group, click the Orientation button. 3.A list of options appears:Choose an option: Angle Counterclockwise: Angles the text in the cell from bottom left to top right.

</span>

Choose an option:

<span>Angle Counterclockwise: Angles the text in the cell from bottom left to top right.Angle Clockwise: Angles the text in the cell from top left to bottom right.Vertical Text: Centers the text and places one letter on top of the other.Rotate Text Up: Places the text on the lower-right side of the cell and runs it vertically up the cell.Rotate Text Down: Places the text on the lower-left side of the cell and runs it vertically down the cell.</span>

ivanzaharov [21]3 years ago

7 0

To rotate text in a cell, select the( text direction) option in the alignment grouping.

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Consider the following arrays. 1 4 21 2 4 100 B # 111(A) L3π 42 Write MATLAB expressions to do the tollowing a. Select just the

andriy [413]

Answer:

Complete Matalb code along with explanation and output results are given below

Explanation:

We are given following two matrices A and B of size 4x3

A = [1 4 2; 2 4 100; 7 9 7; 3 pi 42]

B = log(A)

(a) Select just the second row of B

% to extract any row use this syntax B(row no, : ) we can also extract more than 1 row or any particular elements in a specific row

B_row_2 = B(2,:)

(b) Evaluate the sum of the second row of B

% simply use the sum function and pass it any vector or matrix and it will return their sum

sum_B_row_2 = sum( B_row_2(:) )

(c) Multiply the second column of B and the first column of A element by element

% first we extract the column 2 of matrix B and column 1 of matrix A. use this syntax B( : ,col no ) to extract any column

B_col_2 = B(:,2)

A_col_1 = A(:,1)

% Then we use ( .*) to multiply element by element. To use standard multiplication of matrices only use asterisk sign without coma

multiply=B_col_2.*A_col_1

(d) Evaluate the maximum value in the vector resulting from element-by- element multiplication of the second column of B with the first column of A

% we can find the maximum value in a vector or matrix by using max function so we pass the multiply variable where our result was stored

max_value = max(multiply)

(e) Use element-by-element division to divide the first row of A by the first three elements of the third column of B. Evaluate the sum of the elements of the resulting vector

% First we extract the row 1 of matrix A

A_row_1 = A(1,:)

% Then we extract the column 3 of matrix B

B_col_3 = B(:,3)

% Then we extract the first 3 elements of column 3 of matrix B

B_col_3 = B_col_3(1:3)

% Finally we use ( ./ ) to use element by element division

divide = A_row_1./B_col_3

% Using the sum function again results in the addition of entire elements of resultant matrix

sum_divide = sum( divide(:) )

Only Code:

A = [1 4 2; 2 4 100; 7 9 7; 3 pi 42]

B = log(A)

B_row_2 = B(2,:)

sum_B_row_2 = sum( B_row_2(:) )

B_col_2 = B(:,2)

A_col_1 = A(:,1)

multiply=B_col_2.*A_col_1

max_value = max(multiply)

A_row_1 = A(1,:)

B_col_3 = B(:,3)

B_col_3 = B_col_3(1:3)

divide = A_row_1./B_col_3

sum_divide = sum( divide(:) )

Output Results:

A =

1.0000 4.0000 2.0000

2.0000 4.0000 100.0000

7.0000 9.0000 7.0000

3.0000 3.1416 42.0000

B =

0.00000 1.38629 0.69315

0.69315 1.38629 4.60517

1.94591 2.19722 1.94591

1.09861 1.14473 3.73767

B_row_2 = 0.69315 1.38629 4.60517

sum_B_row_2 = 6.6846

B_col_2 =

1.3863

2.1972

1.1447

A_col_1 =

multiply =

1.3863

2.7726

15.3806

3.4342

max_value = 15.381

A_row_1 = 1 4 2

B_col_3 =

0.69315

4.60517

1.94591

3.73767

B_col_3 =

0.69315

4.60517

1.94591

divide =

1.44270 5.77078 2.88539

0.21715 0.86859 0.43429

0.51390 2.05559 1.02780

sum_divide = 15.216

6 0

3 years ago

How to know your pc does not have bluetooth?

sattari [20]

Assuming you're running Windows, click the start button, and then search for "Device Manager" (or open CMD or PowerShell and type devmgmt.msc). Look at the list of devices. If Bluetooth is there, you have it; if it's not there, you don't.

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3 years ago

HI! THIS IS THE PERSON FROM EARLIER WHO HAD PROBLEMS WITH THEIR PASSWORD

photoshop1234 [79]

Answer:

I dont know anything abt that

Explanation:

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3 years ago

Implement a simplified version of a crypto broker platform. Initially, there is an array of users, with each user depositing onl

Salsk061 [2.6K]

Jriririiekeekekkksks

3 0

3 years ago

What IP address is used as a loopback address and is not a valid IP address that can be assigned to a network

devlian [24]

Answer:

127.0.0.1

Network 127.0. 0.0 is reserved for IP traffic local to your host. Usually, address 127.0. 0.1 will be assigned to a special interface on your host, the loopback interface, which acts like a closed circuit.

Hope this can help you!

4 0

3 years ago