The design of a camshaft-drive system of a four-cylinder automobile engine is shown. As the engine is revved up, the belt speed
v changes uniformly from 3 m/s to 6 m/s over a two-second interval. Calculate the magnitudes of the accelerations of points P1 and P2 halfway through this time interval.
1 answer:
You might be interested in
Answer:
a) the coefficient of performance of the air conditioner is 3.5729
b)
- the power input required for a reversible air conditioner is 0.645 hp
- the coefficient of performance for the reversible air conditioner is 18.2759
Explanation:
Given the data in the question;
Lower Temperature = 70°F = ( 70 + 460 )R = 530 R
Higher Temperature = 99° F = ( 99 + 460 )R = 559 R
Cooling Load = 30000 Btu/h
we know that 1 hp = 2544.43 Btu/h
Net power input P = 3.3 hp = ( 3.3 × 2544.43 )Btu/h = 8396.619 Btu/h
a)
Coefficient of performance of the air conditioner;
= Cooling Load
/ power P
we substitute
= 30000 Btu/h / 8396.619 Btu/h
= 3.5729
Therefore, the coefficient of performance of the air conditioner is 3.5729
b)
- Power input required ( in hp )
/
=
/ (
-
)
we substitute
30000 Btu/h / = 530 R / ( 559 R - 530 R )
30000 Btu/h / = 530 R / 29 R
we solve for
= ( 30000 Btu/h × 29 R ) / 530 R
= ( 870000 Btu/h / 530 )
= 1641.5094 Btu/h
we know that; 1 hp = 2544.43 Btu/h
so;
= ( 1641.5094 / 2544.43 ) hp
= 0.645 hp
Hence, the power input required for a reversible air conditioner is 0.645 hp
- the coefficient of performance for the reversible air conditioner;
=
/ (
-
)
we substitute
= 530 R / ( 559 R - 530 R )
= 530 R / 29 R
= 18.2759
Hence, the coefficient of performance for the reversible air conditioner is 18.2759
Answer:
Therefore, the horizontal displacement of end F of rod EF is 0.4797 mm
Explanation:
solution is mentioned in steps.
