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shepuryov [24]
2 years ago
13

The complete stress distribution obtained by superposing the stresses produced by an axial force and a bending moment is correct

ly represented by _______.
Engineering
1 answer:
Zanzabum2 years ago
7 0

The complete stress distribution obtained by superposing the stresses produced by an axial force and a bending moment is correctly represented by F/A - (My)/(Iz).

<h3>What is the distribution of pressure at some stage in bending?</h3>

Compressive and tensile forces expand withinside the path of the beam axis beneath neath bending loads. These forces set off stresses at the beam. The most compressive pressure is observed on the uppermost fringe of the beam whilst the most tensile pressure is positioned on the decrease fringe of the beam.

The bending pressure is computed for the rail through the equation Sb = Mc/I, wherein Sb is the bending pressure in kilos in keeping with rectangular inch, M is the most bending second in pound-inches, I is the instant of inertia of the rail in (inches)4, and c is the space in inches from the bottom of rail to its impartial axis.

Read more about beam;

brainly.com/question/25329636

#SPJ1

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castortr0y [4]

Yes, the green LED emits light when we connect the banana plug wires across it.

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Explanation:

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siniylev [52]

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3 years ago
#include using namespace std; void PrintFactorial(int factCounter, int factValue){ int nextCounter; int nextValue; if (factCount
bazaltina [42]

Answer:

Check the explanation

Explanation:

Code in C++::

#include <iostream>

using namespace std;

void PrintFactorial(int factCounter, int factValue){

int nextCounter = 0;

int nextValue = 0;

if (factCounter == 0) { // Base case: 0! = 1

cout << "1" << endl;

}

else if (factCounter == 1) { // Base case: Print 1 and result

cout << factCounter << " = " << factValue << endl;

}

else { // Recursive case

cout << factCounter << " * ";

nextCounter = factCounter - 1;

nextValue = nextCounter * factValue;

/* Your solution goes here */

/**

* We just need to call the function PrintFactorial() recursively

* and pass the two parameters that are just calculated as nextCounter for factCounter

* and nextValue as factValue.

*/

PrintFactorial(nextCounter,nextValue);

}

}

int main() {

int userVal = 0;

userVal = 5;

cout << userVal << "! = ";

PrintFactorial(userVal, userVal);

return 0;

}

Output::

Test Case 1 where userVal=5::

<em><u>Attached Image 1</u></em>

Test Case 2 where userVal=6::

<em><u>Attached Image 1</u></em>

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In pea plants, tall height is dominant over short height. How can two tall plants result in a short offspring.
MatroZZZ [7]
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