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3 years ago

RetainingFunction ofWall

Engineering

1 answer:

goblinko [34]3 years ago

7 0

Answer:

A retaining of a wall is a protective structure, first and foremost.

Explanation:

Its main aim is to provide functional support for keeping soil in place. It acts as a wall to keep the soil on one side and the rest of the landscape area on the other, providing a platform for a garden to be created.

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Match each term in the second column with its correct definition in the first column.

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Answer:

The filled in the black answers is:

1. work book

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3 years ago

A reversible compression of 1 mol of an ideal gas in a piston/cylinder device results in a pressure increase from 1 bar to P2 an

Mashutka [201]

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attached below

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soldi70 [24.7K]

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3 years ago

Read 2 more answers

Column arrays: Transpose a row array Construct a row array countValues with elements 1 to endValue, using the double colon opera

White raven [17]

Answer:

Matlab code with step by step explanation and output results are given below

Explanation:

We have to construct a Matlab function that creates a row vector "countValues" with elements 1 to endValue. That means it starts from 1 and ends at the value provided by the user (endValue).

function countValues = CreateArray(endValue)

% Here we construct a row vector countValues from 1:endValue

countValues = 1:endValue;

% then we transpose this row vector into column vector

countValues = countValues';

end

Output:

Calling this function with the endValue=11 returns following output

CreateArray(11)

ans =

Hence the function works correctly. It creates a row vector then transposes it and makes it a column vector.

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3 years ago

Nancy ate a 500 Cal lunch. Neglecting efficiency issues (i.e., assuming 100% conversion of energy to work), to what height could

VladimirAG [237]

Answer:

$4265.04\ \text{m}$

$2.38\times 10^{10}\ \text{W}$

Explanation:

PE = Energy of food = 500 cal = $500\times4184=2.092\times10^6\ \text{J}$

m = Mass of object = 50 kg

g = Acceleration due to gravity = $9.81\ \text{m/s}^2$

Potential energy of food is given by

$PE=mgh\\\Rightarrow h=\dfrac{PE}{mg}\\\Rightarrow h=\dfrac{2.092\times 10^6}{50\times 9.81}\\\Rightarrow h=4265.04\ \text{m}$

Nancy could raise the weight to a maximum height of $4265.04\ \text{m}$ .

Mass of $H_2$ used per year = $25\times 10^{9}\ \text{kg/year}$

Energy of $H_2$ = $\dfrac{30\times10^9}{1000}=30\times 10^6\ \text{J/kg}$

Power

$P=25\times 10^{9}\ \text{kg/year}\times 30\times 10^6\ \text{J/kg}\\\Rightarrow P=7.5\times 10^{17}\ \text{J/year}\\\Rightarrow P=\dfrac{7.5\times 10^{17}}{365.25\times 24\times 60\times 60}\\\Rightarrow P=2.38\times 10^{10}\ \text{W}$

The power requirement is $2.38\times 10^{10}\ \text{W}$ .

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3 years ago

RetainingFunction ofWall​

RetainingFunction ofWall