Where is Eq.(28) ?? You should show it to find the result
Answer:
Explanation:
The additional power consumption of the car when v :
35 mi/h = 0.464hp
70 mi/h = 3.71hp.
For the step by step explanation of how we arrived at these answers, please go through the attached files.
Answer:
total width bandwidth = 8kHz
Explanation:
given data
transmitter operating = 3.9 MHz
frequencies up to = 4 kHz
solution
we get here upper side frequencies that is
upper side frequencies = 3.9 × + 4 × 10³
upper side frequencies = 3.904 MHz
and
now we get lower side frequencies that is
lower side frequencies = 3.9 × - 4 × 10³
lower side frequencies = 3.896 MHz
and now we get total width bandwidth
total width bandwidth = upper side frequencies - lower side frequencies
total width bandwidth = 8kHz
Answer:
The 1st one:Your natural ability