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xenn [34]
3 years ago
12

The sum of two consecutive odd integers is - 108. Find the two integers.

Mathematics
1 answer:
Ulleksa [173]3 years ago
5 0

Answer:

-55 and -53

Step-by-step explanation:

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Solve the system of equations <br><br> 2r - 6y= 28<br> -x-y = 14<br><br><br> PLEASE HELP
o-na [289]

Answer:

\displaystyle [-7, -7]

Step-by-step explanation:

{2x - 6y = 28

{−x - y = 14

−⅙[2x - 6y = 28]

{−⅓x + y = −4⅔

{−x - y = 14

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\displaystyle \frac{-1\frac{1}{3}x}{-1\frac{1}{3}} = \frac{9\frac{1}{3}}{-1\frac{1}{3}} \\ \\

x = -7[Plug this back into both equations above to get the y-coordinate of −7]; \displaystyle -7 = y

I am joyous to assist you anytime.

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4 years ago
What is the expanded form of 114006
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In expanded form :
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Ne4ueva [31]

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Step-by-step explanation:

wrong 95454

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Estimate the size of a crowd at an outdoor concert venue that occupies a rectangular space with dimensions of 500 feet by 1,000
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Describe does Glide Reflection from the preimage triangle and black to the image triangle in red
AveGali [126]

Answer:

d

Step-by-step explanation:

Lets look at V which is at (2,-4).

We will also look at it's image V' which is at (-2,-1).

Let's go through the choices:

a. translation left 4 units and down 1 unit reflection x axis

Translating V left 4 and down 1 would give us (2-4,-4-1)

(-2,-5)

Reflecting that across the x-axis would give us

(-2,5).

So this is not (-2,-1) so let's move on...

b. translation left 2 units and up 2 units reflection line x=1

Translating V left 2 and up 2 gives us

(2-2,-4+2)

(0,-2)

Now reflecting this over x=1 gives us

(2,-2). ( Imagine this x=1 which is verical going right smack between points (0,-2) and (2,-2).)

We still did not reach our goal image.

c. translation left 2 units up and up 3 units reflection y axis

Starting at V(2,-4) and moving left 2 & up 3 gives (2-2,-4+3)=(0,-1).

Now reflecting this over the vertical axis, the y-axis, gives us (0,-1).

So we did not reach our (-2,-1) point yet.

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​Starting at (2,-4) then moving left 2 and up 3 gives us (2-2,-4+3)=(0,-1).

Now we are reflecting over x=-1 which means we want to choose a point on the side making x=-1 the middle. Thuis point on the other side of (0,-1) of x=-1 would be (-2,-1) which is the goal.

8 0
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