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3 years ago

If the area of a square is multiplied by 16, the area becomes 25 square inches. Find the length x of a side of the square.

1 answer:

8 0

1.25 is the length x of a side of the square. Think about it like this. Divide 25 by 16 and you get 1.5625. Then, you do that number squared. So, √1.5625. That gives you 1.25. Hope that helps! Good luck!

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Solve for x in the parallelogram. The solution is x= units.

natka813 [3]

$\textit{area of a parallelogram}\\\\ A=bh~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=13\\ A=104\\ h=x \end{cases}\implies 104=(13)(x)\implies \cfrac{104}{13}=x\implies 8=x$

5 0

2 years ago

What is 32 divided by 147?

liq [111]

The answer is: 0.21768707483

7 0

3 years ago

Read 2 more answers

Write an equation in slope-intercept form for the line that is parallel to y=−4x−3 and that passes through the point (−2,4).

kirill115 [55]

Answer:

The Correct option is Last one $y=-4x-4$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

Step-by-step explanation:

Given:

$y=-4x-3$

To Find:

Equation of line passing through ( -2, 4) and is parallel to the line y=-4x-3

Solution:

$y=-4x-3$ ..........Given

Comparing with Slope-Intercept form,

$y=mx+c$

Where m =slope

We get

$Slope = m = -4$

We know that parallel lines have Equal slopes.

Therefore the slope of the required line passing through (-2 , 4) will also have the slope = m = -4.

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the points and so we will get the required equation of the line,

$(y-4))=-4(x-(-2))=-4x-8\\\\y=-4x-8+4=-4x-4\\\\y=-4x-4......Equation\ of\ line$

Therefore, equation of the line in slope-intercept that passes through (-2,4) and is parallel to the line $y=-4x-3$ is $y=-4x-4$

8 0

3 years ago

If there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices, about w

Liula [17]

32.5 % of lab are wireless devices

Solution:

Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices

Now we can first find out total number of computers and devices in lab

total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices

total number of computers and devices in lab = 30 - 3 + 13 = 40

So there are 40 computers and wireless devices in lab

To find: what percent of the lab are wireless devices

So we have to find what percent of 40 is 13

Let "a" be the required percent

a % of 40 = 13

$\frac{a}{100} \times 40 = 13\\\\a = \frac{13 \times 100}{40}\\\\a = 32.5$

32.5 % of of lab are wireless devices

6 0

3 years ago

Isle Royale, an island in Lake Superior, has provided an important study site of wolves and their prey. Of special interest is t

STatiana [176]

Answer:

Part a) Probability that a moose in that age group is killed by a wolf

P (0.5 year) = 0.361

P (1 - 5) = 0.159

P (6 - 10) = 0.267

P (11 - 15) = 0.203

P (16 - 20) = 0.010

Part b)

Expected age of a moose killed by a wold

μ = 5.61 years

Stantard deviation of the ages

σ = 4.97 years

Explanation:

1) Start by arranging the table to interpret the information:

Age of Moose in years Number killed by woolves

Calf (0.5) 107

1 - 5 47

6 - 10 79

11 - 15 60

16 - 20 3

You can now verify the total number of moose deaths identified as wolf kills: 107 + 47 + 79 + 60 + 3 = 296, such as stated in the first part of the question.

2) First question: a) For each age, group, compute the probability that a moos in that age group is killed by a wolf.

i) Formula:

Probability = number of positive outcomes / total number of events.

ii) Probability that a moose in an age group is killed by a wolf = number of moose killed by a wolf in that age group / total number of moose deaths identified as wolf kills.

iii) P (0.5 year) = 107 / 296 = 0.361

iv) P (1 - 5) = 47 / 296 = 0.159

v) P (6 - 10) = 79 / 296 = 0.267

vi) P (11 - 15) = 60 / 296 = 0.203

vii) P (16 - 20) = 3 / 296 = 0.010

3) Second question: b) Consider all ages in a class equal to the class midpoint. Find the expected age of a moose killed by a wolf and the standard deviation of the ages.

i) Class midpoint

0.5 0.5

1 - 5 (1 + 5) / 2 = 3

6 - 10 (6 + 10) / 2 = 8

11 - 15 (11 + 15) / 2 = 13

16 - 20 (16 + 20) = 18

ii) Expected age of a moose killed by a wolf = mean of the distribution = μ

μ = Sum of the products of each probability times its age (mid point)

μ = 0.5 ( 0.361) + 3 ( 0.159) + 8 ( 0.267) + 13 ( 0.203) + 18 ( 0.010) = 5.61 years

μ = 5.61 years ← answer

iii) Stantard deviation of the ages = σ

σ = square root of the variace

variance = s = sum of the products of the squares of the differences between the mean and the class midpoint time the probability.

s = (0.5 - 5.61)² (0.361) + (3 - 5.61)² ( 0.159) + (8 - 5.61)² ( 0.267) + (13 - 5.61)² ( 0.203) + (18 - 5.61)² ( 0.010) = 24.65

σ = √ (24.65) = 4.97 years ← answer

7 0

3 years ago