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2 years ago

If the area of a square is multiplied by 16, the area becomes 25 square inches. Find the length x of a side of the square.

1 answer:

8 0

1.25 is the length x of a side of the square. Think about it like this. Divide 25 by 16 and you get 1.5625. Then, you do that number squared. So, √1.5625. That gives you 1.25. Hope that helps! Good luck!

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Consider the following hypothesis test: H0: = 18 Ha: ≠ 18 A sample of 48 provided a sample mean LaTeX: \overline{x}x ¯ = 17 and

igomit [66]

Answer:

The value of the test statistic is $t = -1.54$

Step-by-step explanation:

In this problem, we have that:

Null hypothesis

$H_{0} = 18$

Alternate hypothesis

$H_{a} \neq 18$

Compute the value of the test statistic.

This is the value of t, given by

$t = \frac{\overline{x} - \mu_{0}}{\frac{s}{\sqrt{n}}}$

In this problem, we have that:

$\overline{x} = 17, \mu_{0} = 18, s = 4.5, n = 48$ .

$t = \frac{17- 18}{\frac{4.5}{\sqrt{48}}} = -1.54$

The value of the test statistic is $t = -1.54$

4 0

2 years ago

The polygons are similar. find the missing side length

Step2247 [10]

The answer is 16 use cross multiplication

5 0

2 years ago

The height of a triangle is 7 m less than its base. The area of the triangle is 30 m².

Andrej [43]

Answer:

Base 12m Height 5m

Step-by-step explanation:

Area of a triangle formula A=1/2bh

30=1/2(x)(x-7)

2*30 = 1/2(x)(x-7)*2

60 = x^2 -7x

60 - x^2 + 7x = 0

-60 + x^2 -7x = 0

x^2 -7x -60 =0

x^2 + 5x -12x -60 = 0

x(x+5)-12x-60=0

x(x+5)-12(x+5)=0

(x+5)*(x-12)=0

x+5=0

x-12=0

x=-5

x-12=0

x=12

The final answer is: x= 12,5

get rid of the -5 because -5 does not make sense at a height so turn it into 5

Base: 12m

Height 5m

6 0

2 years ago

Read 2 more answers

A tiny but horrible alien is standing at the top of the Empire State Building (which is

Leto [7]

Answer:

87.7 degrees.

Step-by-step explanation:

In triangle ABC, attached.

The height of the building |AB|=443 meters

The distance of the agent across the street , |BC|=18 meters

We want to determine the angle at C.

Now,

$Tan C=\dfrac{|AB|}{|BC|} \\C=arctan (\dfrac{|AB|}{|BC|} )\\=arctan (\dfrac{443}{18} )\\=87.67^\circ\\\approx 87.7^\circ $(correct to the nearest tenth)$

The agent should sfoot his laser gun at an angle of 87.7 degrees.

7 0

3 years ago

If parallel lines a and b are cut by transversal t, then which statement about angles 1 and 2 must be true?

alex41 [277]

Did you not include D or finish writing D since the first three are not right. If one of the possible answers is that they are alternate exterior angles or the same degrees, that would be the answer.

8 0

2 years ago