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2 years ago

What is the median for the set of data?

Mathematics

1 answer:

Masteriza [31]2 years ago

6 0

Answer:

Step-by-step explanation:

2 because it is the middle one and to do the median you have to put the numbers in order so for example, smallest to biggest vice versa and then cross the numbers from each side until you find the middle and if there is one then that is the median and if there is two then you add them together and then divide by 2.

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Factor the expression below. x2 - 4x + 4 A. 4(x2 - x + 1) B. (x - 2)(x + 2) C. (x + 2)(x + 2) D. (x - 2)(x - 2)

Tanzania [10]

Answer:

D. (x - 2)(x - 2)

Step-by-step explanation:

x2 - 4x + 4 = x² - 2x - 2x +4

= x(x-2) - 2(x - 2)

= (x-2)(x-2)

HINT: - 2x +4 = -2 * x + (-2) * (-2) = -2 ( x -2)

4 0

3 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

3 years ago

Xavier is four years younger than twice Zed.

Alex_Xolod [135]

Answer:

Step-by-step explanation:

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7 0

3 years ago

Distribution property 18+45

kvv77 [185]

Answer:

Simplified: its 63 then to 3² · 7

Step-by-step explanation:

3 0

3 years ago

llan needs to prove that overline RS cong overline TU and overline RU cong overline TS . His proof is shown in the table below.

Tju [1.3M]

Answer:

-opposite sides of a parallelogram are congruent.

-definition of a parallelogram

- alternate interior angles are congruent

Step-by-step explanation:

7 0

3 years ago