You would need 6 quarts of milk. You would do 24(2) then you take 48 and divide it by 288 and you get 6.
Answer:
Hope this helps :)
Step-by-step explanation:
15
(3^5)÷(3^5)
Simplify 3^5
243÷243
1
(3^5)÷(3^5)
3^5/3^5=3^5-5
3^5-5
3^5-5= 1
1
Formula: x^a/x^b=x^a-b
16
2^10/2^10
Cancel out 2^10
1
2^10/2^10
2^10/2^10=2^10-10
2^10-10
2^10-10=1
1
Formula: x^a/x^b=x^a-b
17
x^7/x^7x≠0
x≠0
18
(4x+2y)5÷(4x+2y)^5(4x+2y) ≠ 0
5/(4x+2y)^3 ≠ 0
5 ≠ 0
≠ =-y/2
19
No solution
20
p^4/p^4p ≠ 0
p≠ 0
no solution
Answer:
Step-by-step explanation:
Hello!
I'll express all the given percentages as probabilities:
Given the events:
Banking online (Bo)
Under the age of 50 (<50)
P(Bo)= 0.30
P(<50)= 0.40
P(Bo ∩ <50)= 0.25
1) What percentage of adults do not conduct their banking online?
The event "adults that do not conduct their baking online" is the complement of the event "adults that conduct their baking online" Symbolically 
P(
)= 1 - P(Bo)= 1 - 0.30 = 0.70
2) What type of probability is 25%?
The probability P(Bo ∩ <50)= 0.25 is a joint probability, it indicates the intersection between both events.
3) Construct a contingency table showing all joint and marginal probabilities.
Check attachment.
4) What is the probability that an individual conducts banking online given that the individual is under the age of 50?
Symbolically:
P(Bo/<50)= <u> P(Bo ∩ <50) </u> = <u> 0.25 </u> = 0.625
P(<50) 0.40
I hope it helps!
Answer:
<em><u>First</u></em><em><u> </u></em><em><u>Column</u></em><em><u> </u></em><em><u>top</u></em><em><u>:</u></em>
5. 3. 10
<em><u>Second</u></em><em><u> </u></em><em><u>Column</u></em><em><u> </u></em><em><u>middle</u></em><em><u>:</u></em>
9. 7. 2
<em><u>Third</u></em><em><u> </u></em><em><u>Column</u></em><em><u> </u></em><em><u>bottom</u></em><em><u>:</u></em>
4. 8. 6
<em><u>Hence</u></em><em><u>,</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>grid</u></em><em><u> </u></em><em><u>would</u></em><em><u> </u></em><em><u>be</u></em><em><u>,</u></em>
5. 3. 10
9. 7. 2
4. 8. 6