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mote1985 [20]
4 years ago
11

Need help and ASAP please

Mathematics
1 answer:
fgiga [73]4 years ago
7 0

Hi I can’t help you have because half of the question is cut off......

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(08.06 MC)
const2013 [10]

Answer:

  (3.5, 17)

Step-by-step explanation:

It would be nice to see the whole graph, so we can see where the functions cross.

Without that information, we can still eliminate unreasonable choices.

A) the quadratic at y=3.5 is well above the exponential

B) the most likely choice (3.5, 17)

C) at x=-8, the quadratic is above the exponential

D) neither graph goes anywhere near y = -8

8 0
4 years ago
Read 2 more answers
Pls help with qn 13!!!!
balandron [24]
4243.6-4000=243.6/4000= 0.06

Interest rate 0.06%
4 0
3 years ago
How to solve 28,32and34
EastWind [94]
28.) -3 | r + 4| = -21...divide both sides by -3
            | r + 4 | = -21/-3
            | r + 4 | = 7

r + 4 = 7        -(r + 4) = 7
r = 7 - 4          -r - 4 = 7
r = 3                -r = 7 + 4
                       -r = 11
                        r = -11

solution is : r = 3 or r = -11
=======================
32. ) 4| 7y + 2 | - 8 = -7....add 8 to both sides
        4 | 7y + 2 | = -7 + 8
         4| 7y + 2 | = 1 ...divide both sides by 4
          | 7y + 2 | = 1/4

7y + 2 = 1/4                                  -(7y + 2) = 1/4
7y = 1/4 - 2                                   -7y - 2 = 1/4
7y = 1/4 - 8/4                                 -7y = 1/4 + 2
7y = -7/4                                        -7y = 1/4 + 8/4
y = -7/4 * 1/7                                  - 7y = 9/4
y = - 7/28 reduces to - 1/4              y = 9/4 * -1/7
                                                        y = - 9/28

solution is : y = -1/4 or y = -9/28
=========================
34.) I cant see this one
4 0
3 years ago
In ben's class, there were five exams given throughout the semester. if the average of his first four exams was a 90, what was h
balu736 [363]
Number of exams per semester = 5
Average of first four exams = 90

Therefore,
Total of first four exams = 90*4 = 360 marks

Based on 5 exams,

Average = 360/5 = 72
6 0
3 years ago
Find the slope of the line that contains the points named.<br> P(1, 2), Q(3, 4
AnnyKZ [126]
P(1, 2), Q(3, 4)
we find the slope dividing the y over the x, that is:
m = (4 - 2)/(3 - 1) = 2/2
m = 1
and then use the line equation for a point and slope:
y - y1 = m(x - x1)
where (x1, y1) is a point through which the line passes, we use P(1,2):
y - 2 = 2(x - 1)
y - 2 = 2x - 2
y = 2x
therefore the slope is 2 and the y-axis intercept is 0
4 0
4 years ago
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