If you call 
the mass of the ant and 
the load, we have the equation
In fact, the mass of the ant is one tenth of the load, which is exactly what this equation states.
Since we are given the load, we simply need to plug its value in the equation to deduce the mass of the ant:
It would be 8,000 it's simple hope i could help
Answer:
just set the 2 equations equal to each other. answer is 7, 13/3
Step-by-step explanation:
Sec^2 x - 1 = tan^2x
Proof:
Sec^2x = 1+ tan^2x
1/cos^2x = 1 + sin^2x/cos^2x
<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting :
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side
Answer:
Account A: Decreasing at 8 % per year
Account B: Decreasing at 10.00 % per year
Account B shows the greater percentage change
Step-by-step explanation:
Part A: Percent change from exponential formula
f(x) = 9628(0.92)ˣ
The general formula for an exponential function is
y = ab^x, where
b = the base of the exponential function.
if b < 1, we have an exponential decay function.
ƒ(x) decreases as x increases.
Account A is decreasing each year.
We can rewrite the formula for an exponential decay function as:
y = a(1 – b)ˣ, where
1 – b = the decay factor
b = the percent change in decimal form
If we compare the two formulas, we find
0.92 = 1 - b
b = 1 - 0.92 = 0.08 = 8 %
The account is decreasing at an annual rate of 8 %.The account is decreasing at an annual rate of 10.00 %.
Account B recorded a greater percentage change in the amount of money over the previous year.
