Answer:
The probability that the intersection will come under the emergency program is 0.1587.
Step-by-step explanation:
Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.
Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.
For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.
Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).
The values of 
, the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program
The counter example: m∠ ABC = 35°, and m∠ CBD = 25°.
An angle is a figure in Euclidean geometry made up of two rays that share a common terminal and are referred to as the angle's sides and vertices, respectively. Angles created by two rays are in the plane where the rays are located. When two planes intersect each other will create an angle.
Point C is the interior of ABD.
The measure of angle ABD is 60°.
The measure of angle ABC is 40°.
The measure of angle CBD is 20°.
Now when we add the angle ABC and CBD:
∠ ABC + ∠ CBD = 40° + 20°
∠ ABC + ∠ CBD = 60°
∠ ABC + ∠ CBD = ∠ ABD
The counter-example will be:
∠ ABD = ∠ ABC + ∠ CBD
60° = 35° + 25°
Therefore,
∠ ABC = 35° and ∠ CBD = 25°
Learn more about angle here:
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Since the person didn't write the answer choices they were:
A. On average, city A was warmer than city B.
B. The median and mode are different for city B.
C. The temperature range between the maximum and minimum values for city A is greater than the temperature range between the maximum and minimum values for city B.
D. The median is less for city A than for city B.
I believe it is A personally cause i took the test and got it right
Answer:
1) Rolling a 3 is unlikely and rolling a 4 is unlikely too.
2) The probability of niki drawing a green marble is likely and the probability of tom drawing a blue marble is unlikely.
Step-by-step explanation:
1) Since there is only one 3 out of 6 numbers, the probability of that outcome is 1/6, which is low. The same thing goes for throwing a 4.
2) The reason why it is equally likely for niki drawing a green is because there are more green marbles than the other marbles. You could see it as a fraction as well, which is 4/9 Which is very close to one half (4.5). For tom, there are less blue marbles which brings it down to the unlikely spot (fraction = 3/9)
Hopefully this helps, and hopefully it isn't too confusing.
Answer:
6
Step-by-step explanation:
The expression can be rearranged to ...
b = 3 -9/(a+5)
In order for b to be an integer, (a+5) must be an integer divisor of 9. There are exactly 6 of those: ±1, ±3, ±9.
The attached table shows the values (a, b) = (x₁, f(x₁)).
