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rjkz [21]
3 years ago
7

a circle has a radius of 4.5 inches find the length of the arc outlined by a central angle that measures 0.6pi radians

Mathematics
1 answer:
Alex777 [14]3 years ago
5 0

Answer:

8.478in

Step-by-step explanation:

Length of an arc = rtheta

r is the radius of the circle = 4.5in

theta  is the central angle = 0.6pi

Substitute

Length of the arc = 4.5 * 0.6pi

Length of the arc = 4.5 * 0.6 * 3.14

Length of the arc = 8.478inches

Hence the length of the arc is 8.478inches

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Calculate the sum. -16 + (-12) C A. 28 B. 4 C. -4 D. -28
AlexFokin [52]

Answer:

-28

Step-by-step explanation:

-16 +(-12)

= -16 - 12

adding both of them,

= - 28

3 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3
KatRina [158]

Answer:

<h2>B. x = -1, x = -3, y = 0</h2>

Step-by-step explanation:

g(x)=\dfrac{x-2}{x^2+4x+3}\\\\vertical\ asymptote:\\\\x^2+4x+3=0\\x^2+x+3x+3=0\\x(x+1)+3(x+1)=0\\(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\\\\\boxed{x=-1\ \vee\ x=-3}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x-2}{x^2+4x+3}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(\frac{1}{x}-\frac{2}{x^2}\right)}{x^2\left(1+\frac{4}{x}+\frac{3}{x^2}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{\frac{1}{x}-\frac{2}{x^2}}{1+\frac{4}{x}+\frac{3}{x^2}}=\dfrac{0}{1}=0\\\\\boxed{y=0}

4 0
4 years ago
Which expressions are equivalent to the one below? Check all that apply.<br><br>log 2 - log 6
Marina CMI [18]

Answer:

Given the expression: log 2 -log 6

Use the logarithmic rule :

\log(\frac{m}{n}) = \log m - \log n

\log x^n = n\log x

Use the above rule to solve the expression:

\log 2 -\log 6 = \log \frac{2}{6} = \log \frac{1}{3}   [∴\log(\frac{m}{n}) = \log m - \log n ]

or

\log 2 -\log 6 =\log 2+ \log 6^{-1} = \log 2 + \log \frac{1}{6}     [∴\log x^n = n\log x ]

or

value of : log 2 -log 6 = 0.30102999566 - 0.77815125038 = -0.47712125472



7 0
3 years ago
Read 2 more answers
Please answer this now in two minutes
Xelga [282]

Answer:

17.5

Step-by-step explanation:

The following data were obtained from the question:

Angle R = 105°

Side R = r

Side S = 15

Side T = 6

The value of r can be obtained by using cosine rule formula as shown below:

inding sides:

r² = s²+ t² – 2st cos(R)

r² = 15² + 6² – 2 × 15 × 6 × cos105°

r² = 225 + 36 – 180 × cos105°

r² = 261 + 46.587

r² = 307.587

Take the square root of both side

r = √307.587

r = 17.5

Therefore, the value of r is 17.5

7 0
3 years ago
Hey guys please help anything would be helpful at least try
NikAS [45]
I’m in grade 12 and this has me confused lol the wording is weird but my best guess is 180° around point H and then 2 up 5 right
8 0
3 years ago
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