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1 year ago

What is the purpose of adding sodium sulfate to the organic layer after extraction?.

1 answer:

6 0

To remove the water that is in the organic layer. Due to sodium sulfate being a drying agents that will eventually cause water to leave.

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In the winter, a heated home in the Northeast might be maintained at a temperature of 78°F. What is this temperature on the Cels

masya89 [10]

Answer: $25.6^0C$ , $298.6K$

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like $^0C$ and $K$

These units of temperature are inter convertible.

We are given:

Temperature of the gas = $78^0F$

Converting this unit of temperature into $^0C$ by using conversion factor:

$^oC=\frac{5}{9}\times (^oF-32)$

$^0C=\frac{5}{9}\times (78^oF-32)$

$25.6^0C$

Converting this unit of temperature into $K$ by using conversion factor:

$K=t^0C+273$

$K=25.6+273$

$298.6K$

Thus the temperature on the Celsius and Kelvin scales are $25.6^0C$ and $298.6K$ respectively.

6 0

3 years ago

What are the variables that don't change

Blababa [14]

Constant variable/control variable

7 0

3 years ago

GET IT RIGHT FOR BONUS

storchak [24]

Answer:

Sand

Explanation:

with salt distillation will work, heat the solution and collect the water in a seperate beaker

With sugar you do the same, boil away the water and collect the water vapour, you'll be left with sugar in the original container and water if you collected it

Use a fraction of column and heat the solution, the alcohol will be seperated out

Sand is the only one that uses mechanical filtration

5 0

2 years ago

5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf

mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and $pK_{a}$ is as follows.

pH = $pK_{a} + log \frac{base}{acid}$

where, pH = 7.4 and $pK_{a}$ = 7.21

As here, we can use the $pK_{a}$ nearest to the desired pH.

So, 7.4 = 7.21 + $log \frac{base}{acid}$

0.19 = $log \frac{base}{acid}$

$\frac{base}{acid}$ = 1.55

1 mM phosphate buffer means $[HPO_{4}]$ + $[H_{2}PO_{4}]$ = 1 mM

Therefore, the two equations will be as follows.

$\frac{HPO_{4}}{H_{2}PO_{4}}$ = 1.55 ............. (1)

$[HPO_{4}]$ + $[H_{2}PO_{4}]$ = 1 mM ........... (2)

Now, putting the value of $[HPO_{4}]$ from equation (1) into equation (2) as follows.

1.55 $[H_{2}PO_{4}] + [tex][H_{2}PO_{4}]$ = 1 mM

2.55 $[H_{2}PO_{4}]$ = 1 mM

$[H_{2}PO_{4}]$ = 0.392 mM

Putting the value of $[H_{2}PO_{4}]$ in equation (1) we get the following.

0.392 mM + $[HPO_{4}]$ = 1 mM

$[HPO_{4}]$ = (1 - 0.392) mM

$[HPO_{4}]$ = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0

2 years ago

How would this change affect the food web?check all that apply

klio [65]

During the summer, when the land is brown and the grass is green, the population of mice decreases because mice are easily spotted by the organisms that eat them.

How would this change affect the food web? Check all that apply.

A. It will increase the grass population.

D. It will decrease the snake population

E. It will increase the grasshopper population

hope this helps! If so please mark brainliest and rate/heart to help my account if it did!!

7 0

2 years ago