Answer:
The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.
Explanation:
First we have to calculate the heat gained by the calorimeter.
where,
q = Heat gained = ?
c = Specific heat =
ΔT = The change in temperature = 3.08°C
Now put all the given values in the above formula, we get:
Now we have to calculate molar enthalpy of combustion of this substance :
where,
= enthalpy change = ?
q = heat gained = 8.2544kJ
n = number of moles methane =
Therefore, the approximate molar enthalpy of combustion of this substance is -66 kJ/mole.
Answer: This was because the experiment showed that a substance could emit radiation even while it was not exposed to light.
Answer:
say she in love with me say she just want compuny].
Explanation:
Most of the compounds containing C and H are organic so A. CH4 is the correct option