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kati45 [8]
4 years ago
10

How many moles of co2 must enter the calvin cycle for the synthesis of one mole of glucose?

Chemistry
1 answer:
11111nata11111 [884]4 years ago
7 0

Answer:3 moles

Explanation:

For every three molecules of CO2 that enters the Calvin cycle, one molecule of the three carbon glyceraldehyde 3-phosphate (G3P) is produced. Two molecules of G-3-P are required to produce one molecule of glucose. Therefore, the Calvin cycle needs to make a total of 6 turns to produce two molecules of G-3-P.

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Which is the best practice recommended in the safety video to mix and acid or a base with a solvent?
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Read 2 more answers
The rate law for 2NO(g) + O₂(g) → 2NO₂(g) is rate = is rate k[NO]²[O₂]. is rateIn addition to the mechanism in the text (p. 709)
KonstantinChe [14]

The rate law depicts the effect of concentration on reaction rate. Second mechanism 2NO(g) ⇄ N₂O₂(g) [fast], N₂O₂(g) + O₂(g) → 2NO₂(g) [slow] is most reasonable. Thus, option b is correct.

<h3>What is rate law?</h3>

Rate law and equation give the rate at which the reaction takes place under the influence of the concentration of the reactants. The balanced chemical reaction is given as,

2NO(g) + O₂(g) → 2NO₂(g)

The rate of the equation is given as,

rate = k [NO]² [O₂]  

In a multi-step chemical reaction, the slowest step is the rate-determining step. The second mechanism is given as,

2NO (g) → N₂O₂ (g) [fast]

N₂O₂(g) +O₂(g) → 2NO₂ (g) [slow]

Rate is given as,

rate = k [N₂O₂] [O₂]

Therefore, option b. the second mechanism is the most reasonable.

Learn more about rate law, here:

brainly.com/question/14779101

#SPJ4

5 0
2 years ago
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