Answer:
10.28 mol
Explanation:
S + 2O = SO2
(atm x L) ÷ (0.0821 x K)
(3.45 x 45.6) ÷ (0.0821 x 373)
=5.13726
Then round it to significant figures
=5.14
5.14 mol SO2 x (2 mol O ÷ 1 mol SO2)
=10.28 mol O
The transport of O2 from the outside air to tissue cells and the transport of CO2 from tissue cells to the outside is known as.... gas exchange.
Answer:
As specific gravity is defined as weight per unit volume,so urine is the less dense fluid,so urine will be in hyperosmotic category.
