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Minchanka [31]
2 years ago
9

A car accelerates from rest at 6.6 m/s^2. How much time does it need to attain a speed of 7 m/s?

Physics
1 answer:
masha68 [24]2 years ago
4 0

explanation:

Here,

  • initial velocity(u)=0m/s
  • final velocity (v)=7m/s
  • acceleration (a)=6.6m/s²
  • time(t)=?

Using Formula;

v = u + at

or, 7 = 0 + (6.6*t)

or, 7 = 6.6t

or 7/6.6 = t

or, t = 1.06s

I think it will help you....

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B) The lightbulb uses 4,104,000 J more than the stereo.

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2 years ago
A ball of mass 2 kg is kept on the hill of height 3 km. Calculate the potential energy possessed by it ?
zysi [14]
We know that -

P.E=m*g*h

Where,

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P.E.= 2*3000*9.8

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7 0
3 years ago
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2 years ago
An alpha particle (the nucleus of a helium atom) consists of two protons and two neutrons, and has a mass of 6.64 * 10-27 kg. A
melamori03 [73]

Answer:

t = 4.21x10⁻⁷ s

Explanation:

The time (t) can be found using the angular velocity (ω):

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We have:

t = \frac{\theta}{\omega} = \frac{\theta}{v/r}  

<u>Where</u>:      

<em>v: is the tangential speed </em>

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The radius can be found equaling the magnetic force with the centripetal force:

qvB = \frac{mv^{2}}{r} \rightarrow r = \frac{mv}{qB}

Where:

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B: is the magnetic field = 0.155 T

Hence, the time is:

t = \frac{\theta*r}{v} = \frac{\theta}{v}*\frac{mv}{qB} = \frac{\theta m}{qB} = \frac{\pi * 6.64 \cdot 10^{-27} kg}{2*1.6 \cdot 10^{-19} C*0.155 T} = 4.21 \cdot 10^{-7} s

Therefore, the time that takes for an alpha particle to move halfway through a complete circle is 4.21x10⁻⁷ s.

I hope it helps you!    

4 0
3 years ago
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Answer:

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Explanation:

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