Answer:
Solu.tion- salt.water
Suspension- soil mixed water
Colloid- gelatin
Answer:
-10 m/s^2
Explanation:
Acceleration = Change of velocity over time
25/2.5 = 10 m/s^2
Since we are deccelerating here (Going slower) then the number is written as negative
Answer:
Δt = 5.29 x 10⁻⁴ s = 0.529 ms
Explanation:
The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.
![\Delta s = v\Delta t\\\\\Delta t = \frac{\Delta s}{v}](https://tex.z-dn.net/?f=%5CDelta%20s%20%3D%20v%5CDelta%20t%5C%5C%5C%5C%5CDelta%20t%20%3D%20%5Cfrac%7B%5CDelta%20s%7D%7Bv%7D)
where,
Δt = required time interval = ?
Δs = distance between ears = 18 cm = 0.18 m
v = speed of sound = 340 m/s
Therefore,
![\Delta t = \frac{0.18\ m}{340\ m/s}](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20%5Cfrac%7B0.18%5C%20m%7D%7B340%5C%20m%2Fs%7D)
<u>Δt = 5.29 x 10⁻⁴ s = 0.529 ms</u>
Answer:
Length of the chain, l = 0.99 m
Explanation:
Given that,
A playground tire swing has a period of 2.0 s on Earth i.e.
T = 2 s
We need to find the length of this chain. The relationship between the length and the time period is given by :
Where
l = length of chain
g = acceleration due to gravity
![l=\dfrac{T^2g}{4\pi^2}](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7BT%5E2g%7D%7B4%5Cpi%5E2%7D)
![l=\dfrac{(2)^2\times 9.8}{4\pi^2}](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7B%282%29%5E2%5Ctimes%209.8%7D%7B4%5Cpi%5E2%7D)
l = 0.99 meters
So, the length of the chain is 0.99 meters. Hence, this is the required solution.