**b) Vertical component of the velocity: 16.6 m/s (downward)**

**a) The final velocity is 16.6 m/s at below the horizontal**

**Explanation:**

b)

The motion of the fish is a projectile motion, which consists of two independent motions:

- A uniform motion along the horizontal direction

- A vertical motion with constant acceleratio

We start by finding the vertical component of the fish velocity at the moment it hits the water.

To do that, we consider only the vertical motion of the fish, which is a free fall motion, so we can apply suvat equations:

where we have:

= vertical velocity of the fish when it enters the water

initial vertical velocity of the fish

(acceleration of gravity)

s = 14 m vertical displacement

Solving for , we find

in the downward direction.

a)

We can now find the resultant velocity of the fish as it enters the water. In fact, the horizontal velocity remains constant during the entire fall (as there are no forces acting in this direction), and so it is

While we found the vertical velocity to be

So, the magnitude of the final velocity is

And the direction is given as

Learn more about **projectile motion:**

brainly.com/question/8751410

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