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3 years ago

Suppose that a wave has a period of 0.03 second. What’s its frequency?

Physics

2 answers:

soldier1979 [14.2K]3 years ago

6 0

Frequency=1/Period
Frequency=1/0.03s
Frequency=100/3 Hz
Frequency=33.33 Hz

azamat3 years ago

5 0

Answer:

f = 1 ⁄ T

f = 1 ⁄ 0.03

f = 33. 3 Hz

Explanation:

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A river flows at 2m/s. The velocity of a ferry relative to the shore is 4m /s at right angle to the current. What is the velocit

monitta

The velocity of the ferry relative to the current is 4.5 m/s.

<h3>Relative velocity</h3>

Relative velocity is the velocity of a body as observed from the reference point of another body either stationary or in motion.

Since the river is flowing parallel to the shore and the ferry is moving perpendicular to the shore, their velocities are at right angles to each other.

The two velocities form a right angled-triangle of sides 2, 4 and a hypotenuse which gives the relative velocity of the ferry to the current.

Using Pythagoras rule:

c² = a² + b²

Let c be the hypotenuse
a = velocity of the ferry, and
b = the velocity of the current, and

c² = 4² + 2²

c² = 16 + 4

c = 20

c = √20

c = 4.47 m/s

c ≈ 4.5 m/s

Therefore, the velocity of the ferry relative to the current is 4.5 m/s.

Learn more about relative velocity and Pythagoras rule at: brainly.com/question/25617868

5 0

3 years ago

An emission ray has a frequency of 5.10 × 10¹Ê Hz. Given that the speed of light is 2.998 × 10§ m/s, what is the wavelength of t

scoundrel [369]

The answer is 5.88 · 10⁻⁷ m.

To calculate this we will use the light equation:

v = λ · f,
where:
v - the speed of light (units: m/s)
λ - the wavelength of the ray (units: m)
f - the frequency of the ray (units: Hz = 1/s since Hz means cycles per second (f=1/T))

It is given:
f = 5.10 · 10¹⁴ Hz = 5.10 · 10¹⁴ 1/s
v = 2.998 · 10⁸ m/s
λ = ?

If v = λ · f, then λ = v ÷ f:
λ = 2.998 · 10⁸ m/s ÷ 5.10 · 10¹⁴ 1/s
= 0.588 · 10⁸⁻¹⁴ · m
= 0.588 · 10⁻⁶ m
= 5.88 · 10⁻⁷ m

6 0

4 years ago

A rock is dropped from a sea cliff and hits the water 3.2s later. How high is the cliff? How long would it take sound to travel

Kruka [31]

A rock is dropped from a sea cliff and hits the water 3.2s later. How high is the cliff?

t = sqrt(2y/g)
3.2 = sqrt(2y/9.81)
y = 50.23 m

How long would it take sound to travel the same distance?
t = 50.23 / 343 m/s
t = 0.15 s

How long would it take light to travel this distance?
t = 50.23 / 299 792 458 m / s
t = 1.68x10^-7 s

4 0

3 years ago

A 1-kilogram mass is attached to a spring whose constant is 14 N/m, and the entire system is then submerged in a liquid that imp

ch4aika [34]

Answer:

Part(a): The equation of motion is $\bf{x(t) = \dfrac{7}{5}~e^{-2t} - \dfrac{2}{5}~e^{-7t}}$ .

Part(b): The equation of motion is $\bf{x(t) = -e^{-2t} + \dfrac{11}{5}~e^{-7t}}$ .

Explanation:

If ' $m$ ' be the mass of the object, ' $k$ ' be the force constant and ' $\beta$ ' be the damping constant, then the equation of motion of the particle can be written as

$\dfrac{d^{2}x}{dt^{2}} + \dfrac{\beta}{m} \dfrac{dx}{dt} + \dfrac{k}{m}x= 0.........................................(I)$

Given $m$ = 1 Kg, $k$ = 14 $N~m^{-1}$ , $\beta$ = 9. Substituting these values in equation (I),

$\dfrac{d^{2}x}{dt^{2}} + 9~\dfrac{dx}{dt} + 14~x= 0$

Taking a trial solution $x(t) = e^{mt}$ , the auxiliary equation can be written as

$m^{2} + 9m + 14 = 0............................................................(II)$

and its solutions are $m_{1} = -2~and~m_{2} = -7$ , resulting the general solution

$x(t) = C_{1}~e^{-2t} + C_{2}~e^{-7t}....................................................................(III)$

The velocity at any instant of time of the mass is

$v(t) = -2C_{1}~e^{-2t} _7~C_{2}~e^{-7t}..............................................................(IV)$

Part(a):

Given $x(t=0) = 1 m,~and~v(t=0) = 0~m~s^{-1}$ . Substituting these values in equation (III) and (IV),

$&& 1 = C_{1} + C_{2}......................(V)\\&and,& 0 = -2C_{1} - 7C_{2}.......................(VI)$

Solving equations (V) and (VI), we have

$C_{1} = \dfrac{7}{5}~and~C_{2} = \dfrac{-2}{5}$

So the equation of motion is

$x(t) = \dfrac{7}{5}~e^{-2t} - \dfrac{2}{5}~e^{-7t}$

Part(b):

Given $x(t=0) = 1 m,~and~v(t=0) = - 12~m~s^{-1}$ . Substituting these values in equation (III) and (IV),

$&& 1 = C_{1} + C_{2}......................(VII)\\&and,& -12 = -2C_{1} -7C_{2}.......................(VIII)$

Solving equations (V) and (VI), we have

$C_{1} = -1~and~C_{2} = \dfrac{11}{5}$

So the equation of motion is

$x(t) = -e^{-2t} + \dfrac{11}{5}~e^{-7t}$

3 0

4 years ago

Explain how gravity and inertia interact to cause the Earth to revolve around the Sun.

eduard

Answer:

The gravity of the sun and the planets works together with the inertia to create the orbits and keep them consistent. The gravity pulls the sun and the planets together, while keeping them apart. The inertia provides the tendency to maintain speed and keep moving. The planets want to keep moving in a straight line because of the physics of inertia. However, the gravitational pull wants to change the motion to pull the planets into the core of the sun. Together, this creates a rounded orbit as a form of compromise between the two forces.

Explanation:

Hope this answer helps you....

5 0

4 years ago