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3 years ago

Suppose that a wave has a period of 0.03 second. What’s its frequency?

Physics

2 answers:

soldier1979 [14.2K]3 years ago

6 0

Frequency=1/Period
Frequency=1/0.03s
Frequency=100/3 Hz
Frequency=33.33 Hz

azamat3 years ago

5 0

Answer:

f = 1 ⁄ T

f = 1 ⁄ 0.03

f = 33. 3 Hz

Explanation:

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Why do some objects bounce when you throw them at a wall?

Wewaii [24]

Answer:

When you throw a ball against a wall or drop it onto the floor, you notice that it bounces back up again. In the same way, when the ball hits the floor and gets squished, it pushes back against the floor to try to make itself round again.

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3 0

3 years ago

Read 2 more answers

A 3.20 g sample of a salt dissolves in 9.10 g of water to give a saturated solution at 25°C. a. What is the solubility (in g sal

muminat

Answer:

The solubility of the salt is 35.16 (g/100 g of water).

It would take 71.09 grams of water to dissolve 25 grams of salt.

The percentage of salt that dissolves is 52.7 %

Explanation:

We know that 3.20 grams of salt in 9.10 grams of water gives us a saturated solution at 25°C. To find how many grams of salt will gives us a saturated solution in 100 grams of water at the same temperature, we can use the rule of three.

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{x \ g \ salt}{100 \ g \ water}$

Working it a little this gives us :

$x = 100 \ g \ water * \frac{3.20 \g \ salt}{9.10 \ g \ water}$

$x = 35.16 \ g \ salt$

So, the solubility of the salt is 35.16 (g/100 g of water).

Using the rule of three, we got:

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{25 \ g \ salt}{x \ g \ water}$

Working it a little this gives us :

$x = \frac{25 \ g \ salt}{ \frac{3.20 \g \ salt}{9.10 \ g \ water}}$

$x = 71.09 g \ water$

So, it would take 71.09 grams of water to dissolve 25 grams of salt.

Using the rule of three, we got that for 15.0 grams of water the salt dissolved will be:

$\frac{3.20 \g \ salt}{9.10 \ g \ water} = \frac{x \ g \ salt}{15.0 \ g \ water}$

Working it a little this gives us :

$x = 15.0 \ g \ water * \frac{3.20 \g \ salt}{9.10 \ g \ water}$

$x = 5.27\ g \ salt$

This is the salt dissolved

The percentage of salt dissolved is:

$percentage \ salt \ dissolved = 100 \% * \frac{g \ salt \ dissolved}{g \ salt}$

$percentage \ salt \ dissolved = 100 \% * \frac{ 5.27\ g \ salt }{ 10.0 \ g \ salt}$

$percentage \ salt \ dissolved = 52.7 \%$

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