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barxatty [35]
2 years ago
6

Suppose that a wave has a period of 0.03 second. What’s its frequency?

Physics
2 answers:
soldier1979 [14.2K]2 years ago
6 0
Frequency=1/Period
Frequency=1/0.03s
Frequency=100/3 Hz
Frequency=33.33 Hz
azamat2 years ago
5 0

Answer:

f = 1 ⁄ T  

f = 1 ⁄ 0.03  

f = 33. 3 Hz

Explanation:

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The sum of potential and kinetic energies in the particles of a substance is called
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Internal energy.

Explanation:

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The sum of the kinetic energies and potential energies of the particles in a substance is called internal energy.

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2 years ago
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A bird is flying at a velocity of 9m/s holding a 0.85 kg fish. If the bird drops the fish and it falls 14 m to the water below,
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b) Vertical component of the velocity: 16.6 m/s (downward)

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Explanation:

b)

The motion of the fish is a projectile motion, which consists of two independent motions:

- A uniform motion along the horizontal direction

- A vertical motion with constant acceleratio

We start by finding the vertical component of the fish velocity at the moment it hits the water.

To do that, we consider only the vertical motion of the fish, which is a free fall motion, so we can apply suvat equations:

v_y^2 -u_y^2 = 2as

where we have:

v_y = vertical velocity of the fish when it enters the water

u_y = 0 initial vertical velocity of the fish

a=g=9.8 m/s^2 (acceleration of gravity)

s = 14 m vertical displacement

Solving for v_y, we find

v_y = \sqrt{u_y^2+2as}=\sqrt{0+2(9.8)(14)}=16.6 m/s

in the downward direction.

a)

We can now find the resultant velocity of the fish as it enters the water. In fact, the horizontal velocity remains constant during the entire fall (as there are no forces acting in this direction), and so it is

v_x = 9 m/s

While we found the vertical velocity to be

v_y = 14 m/s

So, the magnitude of the final velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{9^2+14^2}=16.6 m/s

And the direction is given as

\theta=tan^{-1}(\frac{v_y}{v_x})=tan^{-1}(\frac{14}{9})=57.3^{\circ}

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2 years ago
Una particula en movimiento aumenta su velocidad e 10cm/s a 20 cm/s en 5 seg. clcular acceleracion
Ostrovityanka [42]

The acceleration of the particle is 2 cm/s^2

Explanation:

The acceleration of a body is defined as follows:

a=\frac{v-u}{t}

where

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v = 20 cm/s

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How many times louder is he orchestra than the sound of the cell phone ringing
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it depends on the ringtone of the phone and what instruments are being played


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Answer:

The beaker that is matt black heats more quickly because black attracts more heat.

Explanation:

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