Suppose that a wave has a period of 0.03 second. What’s its frequency?
2 answers:
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b) Vertical component of the velocity: 16.6 m/s (downward)
a) The final velocity is 16.6 m/s at below the horizontal
Explanation:
b)
The motion of the fish is a projectile motion, which consists of two independent motions:
- A uniform motion along the horizontal direction
- A vertical motion with constant acceleratio
We start by finding the vertical component of the fish velocity at the moment it hits the water.
To do that, we consider only the vertical motion of the fish, which is a free fall motion, so we can apply suvat equations:
where we have:
= vertical velocity of the fish when it enters the water
initial vertical velocity of the fish
(acceleration of gravity)
s = 14 m vertical displacement
Solving for , we find
in the downward direction.
a)
We can now find the resultant velocity of the fish as it enters the water. In fact, the horizontal velocity remains constant during the entire fall (as there are no forces acting in this direction), and so it is
While we found the vertical velocity to be
So, the magnitude of the final velocity is
And the direction is given as
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The acceleration of the particle is
Explanation:
The acceleration of a body is defined as follows:
where
u is the initial velocity of the object
v is the final velocity
t is the time the object takes to change its velocity from u to v
For the particle in this problem, we have:
u = 10 cm/s
v = 20 cm/s
t = 5 s
Substituting into the equation, we find the acceleration:
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