Answer:
We need 375 milliliters of 0.100 M NaHCO3 solution
Explanation:
Step 1: Data given
Initial molarity NaHCO3 = 0.100 M
Volume prepared solution = 750.0 mL
Molarity prepared solution = 0.05 M
Step 2: Calculate initial volume
C1*V1 = C2V2
⇒with C1 = the initial concentration = 0.100 M
⇒with V1 = The initial volume = TO BE DETERMINED
⇒with C2 = the new concentration = 0.0500M
⇒with v2 = the new volume = 750.0 mL = 0.750 L
0.100 M * V1 = 0.0500 M * 0.750 L
V1 = (0.0500M * 0.750L)/0.100 M
V1 = 0.375 L = 375 mL
We need 375 milliliters of 0.100 M NaHCO3 solution
I think sand is just glass and other stuff
Carbon — pay attention to your periodic table trends
Answer:
1.024 x 10⁻²²g
Explanation:
Data Given:
mass of copper = 63.5 g
no. of atoms of copper = 6.02 x10²³ atoms
mass of of an average copper = ?
Solution:
As 6.02 x10²³ atoms have 63.5 g of mass then what will be the mass of atom.
Apply unity formula
63.5 g of copper ≅ 6.02 x10²³ atoms of copper
mass of copper atom ≅ 1 atom of copper
Do cross multiplication
mass of copper atom = 1 atom x 63.5 g / 6.02 x10²³ atoms
mass of copper atom = 1.024 x 10⁻²² g
mass of an average copper atom = 1.024 x 10⁻²² g
