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uranmaximum [27]
2 years ago
6

8 1/3 divided by x=2 1/3 divided by 8.1

Mathematics
1 answer:
givi [52]2 years ago
8 0

Step-by-step explanation:

<u>1. Divide 8 1/3 by 2 to find the value of x:</u>

<u>Turn</u><u> </u><u>8</u><u> </u><u>1</u><u>/</u><u>3</u><u> </u><u>into</u><u> </u><u>an</u><u> </u><u>improper</u><u> </u><u>fraction</u><u>:</u>

8 \frac{1}{3}  =  \frac{3}{3}  +  \frac{3}{3}  +  \frac{3}{3}  +  \frac{3}{3}  +  \frac{3}{3}  +  \frac{3}{3}  +  \frac{3}{3}  +  \frac{3}{3}  +  \frac{1}{3}  =  \frac{25}{3}

\frac{25}{3}  \div  \frac{2}{1}  =  ?

<u>Find the reciprocal (opposite) of 2/1, then multiply:</u>

\frac{25}{3}  \times  \frac{1}{2}  =  \frac{25}{6}  =  \frac{6}{6}  +  \frac{6}{6}  +  \frac{6}{6}  +  \frac{6}{6}   +  \frac{1}{6}  = 4 \frac{1}{6}

x = 25/6 or 4 1/6

<u>2. 8.1 can be put over 1</u><u>:</u>

<u>Turn</u><u> </u><u>2</u><u> </u><u>1</u><u>/</u><u>3</u><u> </u><u>into</u><u> </u><u>an</u><u> </u><u>improper</u><u> </u><u>fraction</u><u>:</u>

2 \frac{1}{3}  =  \frac{3}{3}  +  \frac{3}{3}  +  \frac{1}{3}  =  \frac{7}{3}

\frac{7}{3}  \div  \frac{8.1}{1}  =  ?

<u>Find</u><u> </u><u>the</u><u> </u><u>reciprocal</u><u> </u><u>(</u><u>opposite</u><u>)</u><u> </u><u>of</u><u> </u><u>8</u><u>.</u><u>1</u><u>/</u><u>1</u><u>,</u><u> </u><u>then</u><u> </u><u>multiply</u><u>:</u>

\frac{7}{3}  \times  \frac{1}{8.1}  =  \frac{7}{24.3}

7/24.3 is your simplified answer.

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What 2 numbers equal to 8 when multiplied and 6 when added
expeople1 [14]
2 nuumbers multiply to 8 an addd to 6
factor 8 and add teh factor pairs
1,8
2,4


8+1=9
2+4=6


numbers are 2 and 4

if you were to solve it the
xy=8
x+y=6

y=6-x
x(6-x)=8
6x-x^2=0
0=x^2-6x+8
facotr
0=(x-2)(x-4)
set each to zero
x-2=0
x=2

x-4=0
x=4

x=2 or 4 and since they are interchangable, the numbes are 2 and 4

4 0
3 years ago
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dimulka [17.4K]

Answer:

1 1/20 is the correct way

Step-by-step explanation:

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3 years ago
Write the first five terms of the arithmetic sequence. First term: -10 and common difference: 2
Sholpan [36]

Answer:

The first five terms of the arithmetic sequence.

-10 , -8 , -6 , -4 ,-2 ..........

Step-by-step explanation:

<u><em>Explanation</em></u>

Given that the first term is -10 and common difference d = 2

we know that the sequence in A.P

a ,a+d ,a+2d,a+3d ,a+4d...........  are in AP

-10, -10+2,  -10+2(2),  -10+3(2) , -10+4(2)..................

-10 , -8 , -6 , -4 ,-2 ..........

<u><em>Final answer:-</em></u>

The first five terms of the arithmetic sequence.

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Answer:

?=6

Step-by-step explanation:

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