Use 5 as the lowest common factor and you gt 3/20
Complete question :
The 100m dah times in the girl's track meet were normally distributed with a mean of 13 seconds and a standard deviation of 0.3 seconds.
Lana finished the race in 13.2 seconds . If 84 other girls ran in the event, approximately how many runners did she beat?
Answer:
21 runners
Step-by-step explanation:
Mean, μ = 13 seconds
Standard deviation, σ = 0.3
Lana's race time = 13.2
We find the proportion of runners who had race time above 13.2 ;
Proportion of who had race tune above 13.2
P(x > 13.2)
Obtain the Zscore
Zscore = (x - μ) / σ
Z = (13.2 - 13) / 0.3
Zscore = 0.2 / 0.3 = 0.6667
P(Z > 0.6667) = 0.25239 (Z probability calculator)
This is about 0.25239 * 100 = 25.24% = 25% (nearest percent)
Hence, Number of runners Lana beat = 25% of total runners ;
0.25 * 84 = 21
Hence, Lana beat about 21 runners
Answer:
A = 3244
B = 864
C = 3080
Step-by-step explanation:
700 + a = 3944
-700 -700
a = 3244
3944 - b = c - 80 = 3000
c - 80 = 3000
+80 +80
c = 3080
3944 - b = c ---> 3944 - b = 3080
-3944 -3944
-b = -864 ---> 
Answer:
hw
Step-by-step explanation:
weekly
