6, 16, 26, 36, 46, 56, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 76, 86, 96 so 20 6's
Answer:
c) parabola and circle: 0, 1, 2, 3, 4 times
d) parabola and hyperbola: 1, 2, 3 times
Step-by-step explanation:
c. A parabola can miss a circle, be tangent to it in 1 or 2 places, intersect it 2 places and be tangent at a 3rd, or intersect in 4 places.
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d. A parabola must intersect a hyperbola in at least one place, but cannot intersect in more than 3 places. If the parabola is tangent to the hyperbola, the number of intersections will be 2.
If the parabola or the hyperbola are "off-axis", then the number of intersections may be 0 or 4 as well. Those cases seem to be excluded in this problem statement.
Answer:
≈ 565.5 units²
Step-by-step explanation:
The area (A) of the shaded sector = area of circle × fraction of circle
A = πr² ×
← r is the radius
= π × 20² × 
= 400π × 0.45 ≈ 565.5 units²
Answer:
I’m sorry but I can’t answer until you explain
<h3>I hope it is helpful for you ...</h3>