Answer:
1. SSS
2. Q and S
3. 20
Step-by-step explanation:
1. SSS similarity: If the corresponding sides of two triangles are proportional, then the two triangles are similar.
Triangles NLM and WUV are similar by SSS similarity, because
2. Completed steps:
a) draw a circle with center at P and radius r
b) draw a circle with center at Q and radius r
c) using compass, measure the distance between two points of intersection of the first circle with angle rays
d) using point of intersection of the second circle with PQ as a center, draw the circle of radius equal to the distance from c) to get point S
Last step: connect points Q and S, line QS will be parallel to line r.
3. If lines MN and UT are parallel, then angles MUT and VMN are congruent; also angles UTN and MNV are congruent.
AA similarity: In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar .
By AA similarity, triangles VMN and VUT are similar, thus
Answer:
Hop. Answer ur question the answer is 13
Step-by-step explanation:
yeah hope i helped
First, let's take a look at the formula to figure this out.
m = y2 - y1/x2 - x1
y2 would be -5, and y1 would be 8. -5 - 8 = -13.
x2 is -6, and x1 is also -6. -6 - -6 would be -12.
So, now we must divide -13 and -12, which results in 1 1/12.
No, this is not normal
This is a binomial distribution. Use BINS to determine if this is binomial.
B - binary?
I - independent?
N - number of trials
S - probability of success
B - yes, 3 or not a 3
I - yes, past rolls do not impact future rolls
N - 20 trials
S - prob success 1/6
Use binompdf on your calculator to find out the probability. To access, 2nd —> vars —> binompdf
Binompdf(20 (trials), 1/6 (p), 11 (x)) = 8.97x10^-5
The probability to roll a 3 11 times is .0000897. The chances are very low, making this not normal.
Answer:
B. 1×3
Step-by-step explanation:
Given the first matrix as [ 4 -1 0] this is 1×3 (row by column)
The second matrix is [2 1 0 ] which is a 3×3 matrix
[-3 -7 2 ]
[1 -5 2]
Hence the answer matrix will be;
[1×3 ] *[3×3]----------------------cancel the shaded numbers to remain with
[1×3]
