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2 years ago

what is the equation of the line in slope-intercept form? that has a slope of -2/5 and passes through (15,-2)

Mathematics

1 answer:

Elden [556K]2 years ago

4 0

Answer:

y=3x+11

Step-by-step explanation:

We have to write the equation of line which is passing through the point (−2,5) and parallel to the line y=3x+1. Hence, equation of straight line in point slope form is (y−5)=3(x+2) and in slope-intercept form is y=3x+11

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Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Does anyone know how to do this?

sineoko [7]

Answer:

$\boxed{\tt x=\sqrt{85} }$

Step-by-step explanation:

When making a right triangle with 2 points, the distance is the hypotenuse which can be represent as "x"

To find the distance we can use the Pythagorean theorem.

$\boxed{{\tt a^2+b^2=c^2}}$

→ $\tt a=9$

→ $\tt b=2$

→ $\tt c=x$

Let's Plug in the side lengths:

$\tt 9^2+2^2=x^2$

Evaluate 9²= 81 and 2²= 4:

$\tt 81+4=x^2$

Now, add 81+4= 85

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Take the square root of both sides:

$\tt x=\sqrt{85}$

_____________________________

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3 years ago