Solve the inequality k^2-7k+12.25>0

vodomira [7]

The area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.

<h3>What is the area of the kite figure?</h3>

The area of the kite figure is half of the product of its diagonals. Area of kite figure can be find out using the following formula.

$A=\dfrac{pq}{2}$

Here, p and q are the diagonals of the kite.

The length of the first diagonal of the kite figure is,

p=6+15

p=21 cm

The length of the second diagonal of the kite figure is,

q=8+8

q=16 cm

Thus, the area of kite figure is:

$A=\dfrac{21\times16}{2}\\A=\dfrac{21\times16}{2}\\A=168\rm\; cm^2$

Thus, the area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.

Learn more about the area of kite here;

brainly.com/question/16424656

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8 0

2 years ago

Find the directional derivative of g(x, y) = xey − yex , 2x x − y at the point (1, 0) in the direction v = 3i + 4j

salantis [7]

no rurio greob tryo yeu

7 0

3 years ago

Need help don’t understand the step equation on how to do this

pishuonlain [190]

Answer:

x + y = 125

3.50x + 2.25y = 347.50

53 rolls

Step-by-step explanation:

System of equations

so basically if we say that rolls are represented by x and wrapping paper is represented by y, we can say x plus y is 125 because there are a total of 125 rolls and packages. if each roll is 3.50 and each package is 2.25, we can just put each number in front of the corresponding variable to show that each one is worth that amount, and they total to 347.50. then you have to solve the system of equations. so if you solve for x in the first equation, x = 125 - y. so plug that in to the next equation, 3.50(125 - y) + 2.25y = 347.50. solve for y and you get 72.

but y is the number of packages, and we want the number of rolls. there are 125 rolls and packages, so 125 minus the 72 packages and you get 53 rolls

5 0

2 years ago

Math:<br> Please help me I don’t understand and I need to do corrections.

GREYUIT [131]

So, you had done everything right so far (other than squaring the 2), but that was only half of the question.

to find the least common multiple, you need to first figure out what the prime factors have in common.
${2}^{2} \times 3 \times 5 \\ and \\ {2}^{2} \times {3}^{2} \times 5 \times 7$
each have two twos. both have one 5, so we know our answer will look something like
${2}^{2} \times 5 \times other \: stuff$
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.

one has one 3 and one has two, so we need two threes. now our equation is
${2}^{2} \times {3}^{2} \times 5 \times stuff$

what's the only number we have to deal with? 7...

how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes

4 0

2 years ago

What is the factorization of 49b2 − 81?

Leto [7]

(7b-9)(7b+9)

explanation:
I learned in math last year

6 0

2 years ago