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1 year ago

Finding angles , please help

Mathematics

1 answer:

jek_recluse [69]1 year ago

8 0

Answer:

m∠C = 43.6°, m∠B = 107.4°, b = 51.2

Step-by-step explanation:

Use the law of sines:

a / sin ∠A = c / sin ∠C
26 / sin 29° = 37 / sin ∠C
sin ∠C = 37 sin 29° / 26
sin ∠C = 0.6899
m∠C = arcsin 0.6899
m∠C = 43.6°

Find the missing angle:

m∠B = 180° - 29° - 43.6° = 107.4° (rounded)

Use the law of sines to find the length of b:

a / sin ∠A = b / sin ∠B
26 / sin 29° = b / sin 107.4°
b = 26 sin 107.4° / sin 29°
b = 51.2 units (rounded)

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Read 2 more answers

Please answer with explanation, I don't understand. <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E2-14x%2B49%7D%20%3Dx

Crank

Answer: x ≥ 7

Step-by-step explanation:

You have to square both sides of the equation. You can manipulate an equation or function any way imaginable as long as it is done equally and helps the problem become easier. If we square this, the radical will cancel and we will get two trinomials equal to each other.

$x^2-14x+49=(x-7)^2\\x^2-14x+49=x^2-14x+49$

We can see the two expressions are exactly equal to each other. All real numbers are solutions, besides a few. These few are when the radical is equal to a negative number. So lets set up an inequality stating that the radical must be greater than or equal to 0.

$x^2-14x+49\geq 0\\(x-7)^2 \geq 0\\x \geq 7$

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