Answer:
(x + 39) or x = -39
Step-by-step explanation:
Set f(x) to 0
0 = 5x + 195
5x = -195
x = -39
Answer:
Step-by-step explanation:

Auxialary equation is

General solution is



Eliminate B to get
3A =a-1
We know that y tends to 0 when x tends to infinity for any finite A
i.e. a should be a finite real number.
Answer:
Two imaginary solutions:
x₁= 
x₂ = 
Step-by-step explanation:
When we are given a quadratic equation of the form ax² +bx + c = 0, the discriminant is given by the formula b² - 4ac.
The discriminant gives us information on how the solutions of the equations will be.
- <u>If the discriminant is zero</u>, the equation will have only one solution and it will be real
- <u>If the discriminant is greater than zero</u>, then the equation will have two solutions and they both will be real.
- <u>If the discriminant is less than zero,</u> then the equation will have two imaginary solutions (in the complex numbers)
So now we will work with the equation given: 4x - 3x² = 10
First we will order the terms to make it look like a quadratic equation ax²+bx + c = 0
So:
4x - 3x² = 10
-3x² + 4x - 10 = 0 will be our equation
with this information we have that a = -3 b = 4 c = -10
And we will find the discriminant: 
Therefore our discriminant is less than zero and we know<u> that our equation will have two solutions in the complex numbers. </u>
To proceed to solve the equation we will use the general formula
x₁= (-b+√b²-4ac)/2a
so x₁ = 
The second solution x₂ = (-b-√b²-4ac)/2a
so x₂=
These are our two solutions in the imaginary numbers.
The answer is <span>A)(13, 8).
Distance I to F is: yf - yi = -1 - (-4) = -1 + 4 = 3
Distance D to A is: ya - yd = 8 - 2 = 6
</span>Distance D to A : Distance I to F = 6 : 3<span>
6 : 3 = 2, so scale factor is 2.
Among all choices, we see that the y point of another corner is 8, so we need to find x point.
Distance I to H is: xh - xi = -2 - (-7) = -2 + 7 = 5
Distance A to x corner is: x - xa = x - 3
Since </span>Distance I to H is 5, and scale factor is 2, we have:
Distance A to x corner : Distance I to H = 2
Distance A to x corner = 2 * Distance I to H = 2 * 5 = 10
Distance A to x corner is: xa - x = x - 3 = 10
x - 3 = 10
x = 10 + 3
x = 13