Answer:
P1 =4 atm
T1= 20°C
P2=1 atm
T2=?
According to Gay-Lussac's Law or Third Gas Law,
P1T2=P2T1
4×T2=1×20
T2= 20/4
T2= 5°C
Answer At 5°C temperature does a gas at 1.00 atm !
Al +3CuCl--->AlCl3+3Cu , its balanced equation
As the temperature increases, the solubility of the solute in the liquid also increases. This is due to the fact that the increase in energy allows the liquid to more effectively break up the solute. The additoin of energy also shifts the equilibrium of the reation to the right since it takes energy to dissolve most things and you are adding more of it (this is explained with Le Chatlier principles).
I hope this helps and also I assumed that your question involved the solubility of an ionic substance in a solvent like water. If that was not your question feel free to say so in the comments so that I can answer your actually question.
Answer:
T₂ = 859.4 K
Explanation:
Given data:
Initial volume of gas = 32.0 L
Initial temperature = 2°C (2 + 273 = 275 k)
Final temperature = ?
Final volume = 1.00 ×10²L
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
T₂ = V₂T₁ /V₁
T₂ = 1.00 ×10²L × 275 K / 32.0 L
T₂ = 27500 L.K / 32.0 L
T₂ = 859.4 K
