Answer:
1.
Explanation:
Hello,
In this case, for the given reaction we first assign the oxidation state for each species:
![Sn^0 + H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 + N^{4+}O^{2-}_2 + H^+_2O^-](https://tex.z-dn.net/?f=Sn%5E0%20%2B%20H%5E%2BN%5E%7B5%2B%7DO%5E%7B-2%7D_3%20%5Crightarrow%20Sn%5E%7B4%2B%7DO_2%20%2B%20N%5E%7B4%2B%7DO%5E%7B2-%7D_2%20%2B%20H%5E%2B_2O%5E-)
Whereas the half reactions are:
![Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O](https://tex.z-dn.net/?f=Sn%5E0%2B2H_2O%20%5Crightarrow%20Sn%5E%7B4%2B%7DO_2%20%2B4H%5E%2B%2B4e%5E-%5C%5C%5C%5CH%5E%2B%2BH%5E%2BN%5E%7B5%2B%7DO%5E%7B-2%7D_3%20%2B1e%5E-%5Crightarrow%20%20N%5E%7B4%2B%7DO%5E%7B2-%7D_2%2BH_2O)
Next, we exchange the transferred electrons:
![1\times(Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-)\\\\4\times (H^++H^+N^{5+}O^{-2}_3 +1e^-\rightarrow N^{4+}O^{2-}_2+H_2O)\\\\\\Sn^0+2H_2O \rightarrow Sn^{4+}O_2 +4H^++4e^-\\\\4H^++4H^+N^{5+}O^{-2}_3 +4e^-\rightarrow 4N^{4+}O^{2-}_2+4H_2O](https://tex.z-dn.net/?f=1%5Ctimes%28Sn%5E0%2B2H_2O%20%5Crightarrow%20Sn%5E%7B4%2B%7DO_2%20%2B4H%5E%2B%2B4e%5E-%29%5C%5C%5C%5C4%5Ctimes%20%28H%5E%2B%2BH%5E%2BN%5E%7B5%2B%7DO%5E%7B-2%7D_3%20%2B1e%5E-%5Crightarrow%20%20N%5E%7B4%2B%7DO%5E%7B2-%7D_2%2BH_2O%29%5C%5C%5C%5C%5C%5CSn%5E0%2B2H_2O%20%5Crightarrow%20Sn%5E%7B4%2B%7DO_2%20%2B4H%5E%2B%2B4e%5E-%5C%5C%5C%5C4H%5E%2B%2B4H%5E%2BN%5E%7B5%2B%7DO%5E%7B-2%7D_3%20%2B4e%5E-%5Crightarrow%20%204N%5E%7B4%2B%7DO%5E%7B2-%7D_2%2B4H_2O)
Afterwards, we add them to obtain:
![Sn^0+2H_2O+4H^++4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4H^++4N^{4+}O^{2-}_2+4H_2O](https://tex.z-dn.net/?f=Sn%5E0%2B2H_2O%2B4H%5E%2B%2B4H%5E%2BN%5E%7B5%2B%7DO%5E%7B-2%7D_3%20%20%5Crightarrow%20Sn%5E%7B4%2B%7DO_2%20%2B4H%5E%2B%2B4N%5E%7B4%2B%7DO%5E%7B2-%7D_2%2B4H_2O)
By adding and subtracting common terms we obtain:
![Sn^0+4H^+N^{5+}O^{-2}_3 \rightarrow Sn^{4+}O_2 +4N^{4+}O^{2-}_2+2H_2O](https://tex.z-dn.net/?f=Sn%5E0%2B4H%5E%2BN%5E%7B5%2B%7DO%5E%7B-2%7D_3%20%20%5Crightarrow%20Sn%5E%7B4%2B%7DO_2%20%2B4N%5E%7B4%2B%7DO%5E%7B2-%7D_2%2B2H_2O)
Finally, by removing the oxidation states we have:
![Sn + 4HNO_3 \rightarrow SnO_2 + 4NO_2 + 2H_2O](https://tex.z-dn.net/?f=Sn%20%2B%204HNO_3%20%5Crightarrow%20SnO_2%20%2B%204NO_2%20%2B%202H_2O)
Therefore, the smallest whole-number coefficient for Sn is 1.
Regards.
Answer:
The DNA is cut using special chemicals called restriction enzymes,.
DNA ligase are used to insert genes and other pieces of DNA into plasmids.
Answer:
covalent
Explanation:
C2S6 is a compound made of 2 nonmetals which makes it covalent
Hope this helps! Plz mark brainliest
A) Burning
Burning is a chemical reaction while the other three answers are physical reactions.