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2 years ago

Please help in math!! Solution needed

Mathematics

2 answers:

Marysya12 [62]2 years ago

5 0

This is the same as any math problem you may have solved before.

First, start by isolating the x on one side. I will choose to keep the coefficient positive, so I will add x to both sides.

6>2x+2

Subtract 2

4>2x

Divide by 2

2>x

Or

x<2

earnstyle [38]2 years ago

4 0

X<2 or 2>X is the answer I believe

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Answer:

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Step-by-step explanation:

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2 years ago

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Andreyy89

Answer:

(a) $9z+2=5$

(b) $21z-11=-4$

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

Equation 1

$z=\frac{1}{3}$

Multiply both sides by 9

$9z=\frac{1}{3}\times 9\\9z=3$

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Add 2 to both sides

Our first equation is: $9z+2=5$

Equation 2

$z=\frac{1}{3}$

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21z=11-4

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$z=\frac{1}{3}$

Multiply both sides by 6

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Rewrite 6z as 4z+2z

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Subtract 2z from both sides

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