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Greeley [361]
3 years ago
15

Complete the transmutation equation below. Assume that there is only one unknown product. Np93239→Pu94239+?

Chemistry
1 answer:
aliya0001 [1]3 years ago
5 0
I have attached the answer. hopefully, i read the problems correctly. let me know if I did not.

both problems are an example of beta decays. when an atoms' atomic number is increased by one. this is symbolized with -1 e

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This refers to the most powerful means of communicating confidence and conviction A.Posture B.eye contact C.body movement
skad [1K]

Answer:

c

Explanation:

the way you move explains how confident you are

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3 years ago
When an atom makes a transition from a higher energy level to a lower one, a photon is released. What is the wavelength of the p
kykrilka [37]

Answer:

Wavelength of the photon depends on transition from different states.

Explanation:

The wavelength of the photon that is emitted from the atom during the transition depends on the transition from different states. If the photon is emitted from n=4 state to n=3 state, the wavelength of photon is 1875 while on the other hand, if the photon is emitted from n=5 state to n=3 state, the wavelength of photon is 1282. If the photon is emitted from n=3 state to n=2 state, the wavelength of photon is 656.

4 0
2 years ago
The ideal gas law equation is: PV = nRT
nignag [31]

Answer:

The answer is the first option 0.37 moles

Explanation:

the ideal gas law is PV = nRT, so in the terms of n,

n = PV/RT (divide both sides by RT to let n stand alone)

given: P = 700 kpa, V = 2L, T = 450 K , R = 8.31

n = (700 * 2) / (8.31 * 450)

= 1400/3739.5

= 0.34

8 0
2 years ago
Electrons and the Periodic Table
White raven [17]

Answer:

The third one

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6 0
3 years ago
A gas exerts a pressure of 1.8 atm at a temperature of 60 degrees celsius. What is the new temperature when the pressure of the
Kamila [148]

The answer for the following problem is mentioned below.

  • <u><em>Therefore the final temperature of the gas is 740 K</em></u>

Explanation:

Given:

Initial pressure of the gas (P_{1}) = 1.8 atm

Final pressure of the gas (P_{2})  = 4 atm

Initial temperature of the gas (T_{1}) = 60°C = 60 + 273 = 333 K

To solve:

Final temperature of the gas (T_{2})

We know;

From the ideal gas equation;

we know;

P  × V = n × R × T

So;

we can tell from the above equation;

 <u>   P ∝ T</u>

(i.e.)

      <em> </em>\frac{P}{T}<em> = constant</em>

        \frac{P_{1} }{P_{2} } = \frac{T_{1} }{T_{2} }

Where;

P_{1}  = initial pressure of a gas

P_{2} = final pressure of a gas

T_{1} = initial temperature of a gas

T_{2} = final temperature of a gas

        \frac{1.8}{4} = \frac{333}{T_{2} }

   T_{2} =\frac{333*4}{1.8}

    T_{2} = 740 K

<u><em>Therefore the final temperature of the gas is 740 K</em></u>

8 0
3 years ago
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