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Tanya [424]
3 years ago
11

How does the number of valence electrons for elements change across a period?

Chemistry
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer: Option (b) is the correct answer.

Explanation:

Valence electrons is the number of electrons present in the outermost shell of an atom.

So, when we move across a period from left to right then there will be increase in number of valence electrons.

For example, valence electrons in carbon is 4, nitrogen has 5 valence electrons, oxygen has 6 valence electrons.

Thus, we can conclude that number of valence electrons increases for elements change across a period.

NeTakaya3 years ago
4 0
D. The number increases and then decreases for noble gases
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Please help :) ill mark you as the brainiest hope you have a good day
Hitman42 [59]

Have a wonderful day :) thanks for the points

5 0
3 years ago
Plz help ASAP. thx for you answers​ ALGEBRA 2 sorry
iren [92.7K]

So, the answer to 27.) would be <em>2x.</em> Both 6x and 2x can be divided by 2x, but they can't go any higher without the end-answer becoming a fraction. As such, 2x is the greatest common factor.

For 28.), x and x^2 can't be like terms, since like terms have the same variable and exponent :)

Hope I could help!

3 0
3 years ago
If 45 mL of water are added to 250 mL of a 0.75 M K2SO4 solution, what will the molarity of the diluted solution be?
krok68 [10]

Answer:

\large\boxed{\large\boxed{0.64M}}

Explanation:

When you form a <em>diluted solution</em> from a mother (concentrated) solution, the moles of solute are determined by the mother solution.

The main equation is:

Molarity=\dfrac{\text{moles of solute}}{\text{volume of the solution in liters}}

Then, since the moles of solute is the same for both the mother solution and the diluted solution:

          \text{Molarity mother solution }\times\text{ volume mother solution}=\\\\=\text{Molarity diluted solution }\times\text{ volume diluted solution}

Substitute and solve for the molarity of the diluted solution:

           250mL\times 0.75M=(45mL+250mL)\times M\\\\\\M=\dfrac{250mL\times 0.75M}{295mL}=0.64M

8 0
3 years ago
In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions)
jeyben [28]

Answer:

Li2S> Na2S> K2S> CsS

Explanation:

The lattice energy of ionic species depends on the relative sizes of ions in the ionic compounds. As the size of ions increases, the lattice energy decreases and vice versa.

When the size of the anions are the same, the lattice energy now depends on the relative sizes of the cations. Therefore, since all the compounds are sulphides and the order of magnitude of ionic sizes is: Li^+ < Na^+ < K^+ < Cs^+.

Therefore, the order of decrease in lattice energy is; Li2S> Na2S> K2S> CsS

7 0
3 years ago
In a lab, a student dissolves 6.9 g of sodium chloride (NaCl) in 125 g of water (H2O).
kati45 [8]
Hope it cleared your doubt.

5 0
3 years ago
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