Blue should be added somewhere. , than yellow, lastly red+black
Blue, oxygen+hydrogen, carbon+oxygen.
It will most likely get flooded at one point in time.
Answer:
a.3-5 is the modal class.
Answer is: molar mass
of compound is 154,58 g/mol.<span>
m(</span>naphthalene<span>) = 10 g = 0,01 kg.
m(unknown compound) = 1,00 g.
</span>Δ<span>T (solution) = 4,47 °C.
Kf(</span>naphthalene) = 6,91°C/m<span>; cryoscopic
constant.
M</span>(unknown compound) = Kf(naphthalene)· m(unknown compound) ÷
m(naphthalene)<span> · ΔT(solution).
M(xylene) = </span>6,91°C/m<span> · 1 g ÷ 0,01 kg · 4,47</span>°C<span>.
M(xylene) = 154,58 g/mol.</span>
Answer:
64 moles
Explanation:
Let us begin by writing a balanced equation for the reaction. This is illustrated below:
2Na + Cl2 —> 2NaCl
From the equation above,
1 mole of Cl produced 2 moles of NaCl.
Therefore, 32 moles of Cl will produce = 32 x 2 = 64 moles of NaCl.
Therefore, 64 moles of NaCl are produced
