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4 years ago

Which of the following is not harmed by acid rain?

Chemistry

2 answers:

Paul [167]4 years ago

7 0

B) Glass Windows..... Hope it helps :)

DiKsa [7]4 years ago

5 0

Answer: glass windows

Explanation:

An acid rain is appears when the sulfur oxide and nitrous oxide present in the atmosphere get mixed with the water vapors forms sulphuric acid and nitric acid in the atmosphere which comes down in the biosphere in the form of precipitation called as acid rain. The acid rain is capable of causing damage to the building materials such as concrete, marble, cement also capable of causing corrosion of the iron.

The acid rain has no effect over the glass windows because of the fact that glass is a solid hard material which cannot be damaged by the any kind of chemical such as acids or alkalies.

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Atoms of which two elements have a combined total of 23 protons?

Alik [6]

Answer:

Sodium, Na, and magnesium, Mg

6 0

4 years ago

Carbon tetrachloride can be produced by the following reaction: Suppose 1.20 mol of and 3.60 mol of were placed in a 1.00-L flas

hjlf

The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Suppose 1.20 mol $CS_2(g)$ of and 3.60 mol of $Cl_2(g)$ were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol of $CCl_4$ . Calculate equilibrium constant at the unknown temperature.

Answer: The equilibrium constant at unknown temperature is 0.36

Explanation:

Moles of $CS_2$ = 1.20 mole

Moles of $Cl_2$ = 3.60 mole

Volume of solution = 1.00 L

Initial concentration of $CS_2$ = $\frac{moles}{volume}=\frac{1.20mol}{1L}=1.20M$

Initial concentration of $Cl_2$ = $\frac{moles}{volume}=\frac{3.60mol}{1L}=3.60M$

The given balanced equilibrium reaction is,

$CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)$

Initial conc. 1.20 M 3.60 M 0 0

At eqm. conc. (1.20-x) M (3.60-3x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}$

Now put all the given values in this expression, we get :

$K_c=\frac{(x)\times (x)}{(3.60-3x)^3\times (1.20-x)}$

Given :Equilibrium concentration of $CCl_4$ , x = $\frac{moles}{volume}=\frac{0.72mol}{1L}=0.72M$

$K_c=\frac{(0.72)\times (0.72)}{(3.60-3\times 0.72)^3\times (1.20-0.72)}$

$K_c=0.36$

Thus equilibrium constant at unknown temperature is 0.36

4 0

3 years ago

What is the molecular formula of a compound containing 89% cesium (Cs) and 11% oxygen (O) with a molar mass = 298 g/mol?

Maurinko [17]

M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11

CsxOy

x=M(CsxOy)w(Cs)/M(Cs)
x=298*0.89/133=2

y=M(CsxOy)w(O)/M(O)
y=298*0.11/16=2

Cs₂O₂ cesium peroxide

6 0

3 years ago

Read 2 more answers

how much hydrogen gas is necessary to exert a pressure of 1.4 ATM at 430k if occupying a volume of 15.1 l

lora16 [44]

Answer:

Explanation:

7 0

3 years ago

Don’t mind my cats fur :)

denpristay [2]

Answer:

Potassium is an element, with the symbol K

Explanation:

An element is something that cannot be broken down any further, for example, calcium, its Ca.

A compound is when you bond two or more elements. Compounds can be broken down into its original elements, for example, H₂O, it contains two atoms of hydrogen and one atom of oxygen (both hydrogen and oxygen are elements).

8 0

3 years ago