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MariettaO [177]
3 years ago
13

Which of the following is not harmed by acid rain?

Chemistry
2 answers:
Paul [167]3 years ago
7 0
B) Glass Windows..... Hope it helps :)
DiKsa [7]3 years ago
5 0

Answer: glass windows

Explanation:

An acid rain is appears when the sulfur oxide and nitrous oxide present in the atmosphere get mixed with the water vapors forms sulphuric acid and nitric acid in the atmosphere which comes down in the biosphere in the form of precipitation called as acid rain. The acid rain is capable of causing damage to the building materials such as concrete, marble, cement also capable of causing corrosion of the iron.

The acid rain has no effect over the glass windows because of the fact that glass is a solid hard material which cannot be damaged by the any kind of chemical such as acids or alkalies.

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Hydrochloric acid reacts with calcium to form hydrogen and calcium chloride. If 100 grams of hydrochloric acid reacts with 100 g
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Calculate the Kc for the following reaction if an initial reaction mixture of 0.500 mole of CO and 1.500 mole of H2 in a 5.00 li
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2 years ago
A 59.1g sample of aluminum is put into a calorimeter (see sketch at right) that contains 250.0g of water. The aluminum sample st
Rainbow [258]

Answer:

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

Explanation:

Step 1: Data given

Mass of aluminium = 59.1 grams

Mass of water = 250.0 grams

Initial temperature of aluminium = 91.3 °C

Initial temperature of water = 16.0 °C

Final temperature = 19.5 °C

Pressure remains constant

Specific heat capacity of water = 4.186 J/g°C

Step 2: Calculate specific heat of aluminium

Heat lost = heat gained

Qlost = -Q heat

Q = m*c*ΔT

heat aluminium = - heat water

m(aluminium) * c(aluminium) * ΔT(aluminium) = -m(water) * c(water) * ΔT(water)

⇒m(aluminium) = mass of aluminium = 59.1 grams

⇒c(aluminium) = the specific heat of aluminium = TO BE DETERMINED

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 91.3 = -71.8 °C

⇒ m(water) = 250.0 grams

⇒c(water) = the specific heat of water = 4.186 J/g°C

⇒ΔT = the change in temperature = T2 -T2 = 19.5 - 16.0 = 3.5 °C

59.1 * c(aluminium) * -71.8 °C = 250.0 * 4.186 J/g°C * 3.5 °C

c(aluminium) = 0.863 J/g°C

The specific heat capacity of aluminum according to this experiment is 0.863 J/g°C

3 0
2 years ago
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