Answer:
0.32 M
Explanation:
Step 1: Write the balanced reaction at equilibrium
Ag₂S(s) ⇌ 2 Ag⁺(aq) + S²⁻(aq)
Step 2: Calculate the concentration of Ag⁺ at equilibrium
We will use the formula for the concentration equilibrium constant (Keq), which is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species.
Keq = [Ag⁺]² × [S²⁻]
[Ag⁺] = √{Keq / [S²⁻]}
[Ag⁺] = √{2.4 × 10⁻⁴ / 0.0023} = 0.32 M
Answer:
C. The reaction is energetically favorable.
Explanation:
The reaction which shows the removal of the terminal phosphate from the ATP is shown below:
The Gibbs' free energy change of this reaction, 
Hence, Option A is not correct.
It is a type of hydrolysis reaction in which water is being added to the molecule.
Hence, Option B is not correct.
The Gibbs' free energy change is negative which means that the reaction is energetically favorable.
Option C is correct.
Answer:
Sediment moves from one place to another through the process of erosion. Erosion is the removal and transportation of rock or soil. Erosion can move sediment through water, ice, or wind. Water can wash sediment, such as gravel or pebbles, down from a creek, into a river, and eventually to that river's delta.
Explanation:
