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Mandarinka [93]
3 years ago
9

Eukaryote:mitosis:: prokaryote:

Chemistry
1 answer:
poizon [28]3 years ago
3 0

The process of cell division is different in prokaryotes and eukaryotes as prokaryotes have a primitive cell structure which is not membrane bound. In eukaryotes the process of cell division is termed as mitosis. In prokaryotic cells like a bacterial cell, the cell divides by a process called binary fission, where each cell is cleaved into two identical cells each with its own chromosomal set.  Budding is process of asexual reproduction and is different from cell division.

Therefore, the correct answer will be a. binary fission.

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3. What noble gas would be part of the electron configuration notation for Mn?
shusha [124]

Answer:

Argon {Ar}

Explanation:

The noble gas used for a condensed electron configuration is the one before the element which you are configuring.

In this case, the element (Mn) is manganese

The noble gas that is before this element is Argon which is the row above it

so your configuration would be {Ar} 3d^5 4s^2

7 0
3 years ago
Draw the orbital notation for the element Boron
Wewaii [24]

Answer:

I can't draw but you could draw 2 electrons in the first orbit and 3 electrons in the second orbit.

Explanation:

6 0
2 years ago
Read 2 more answers
A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?
Lunna [17]

Answer:

80L

Explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

V2 = ?

V2 = V1 T2/T1

V2 = (60L)(400K) / (300K)

V2 = 80L

7 0
2 years ago
1. EXPLAIN the steps required to find the molar mass of NH3 . Also,
Natasha_Volkova [10]

Answer: Molar mass of NH_3 is 17.03 g

Explanation:

Molar mass is defined as the mass in grams of 1 mole of a substance.

S.I Unit of Molar mass is gram per mole and it is represented as g/mol.

It is found by adding the atomic masses of all the elements present.

Atomic Mass of Nitrogen (N) = 14.007 g

Atomic Mass of Hydrogen (H) = 1.008 g

Molar mass of NH_3 = 1(14.007)+3(1.008) g = 17.03 g

7 0
3 years ago
Given the following data in the Determination of Molar Mass of CO2 lab : Mass (before rxn): test tube HCl(aq) stir bar capsule 2
RSB [31]

Answer:

.259 g

Explanation:

PV = nRT

n = PV / RT

= .986 x 0.144 / .082 x 293.6

= .005897 moles

= .005897 x 44 g

= .259 g

3 0
2 years ago
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