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Andreyy89
3 years ago
11

Help please!!! Do you think we always see the same side of the Moon?

Physics
1 answer:
Reika [66]3 years ago
3 0

Answer:

yess

Explanation:

"The Moon orbits Earth once every 27.3 days and spins on its axis once every 27.3 days. This means that although the Moon is rotating, it always keeps one face toward us. Known as “synchronous rotation,” this is why we only ever see the Moon's nearside from Earth."

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What do you know about velocity, acceleration and reference frame?
kozerog [31]

Answer:

The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).

Acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down. ... Acceleration is defined as the change in the velocity vector in a time interval, divided by the time interval.

In physics and astronomy, a frame of reference consists of an abstract coordinate system whose origin, orientation, and scale are specified by a set of reference points ― geometric points whose position is identified both mathematically and physically.

4 0
3 years ago
A teenager of mass m1 = 72 kg pushes backward against the ground with his foot as he rides his skateboard. This exerts a horizon
Ray Of Light [21]

Answer:

The acceleration of the skateboard is -9.65 m/s².

Explanation:

Given that,

Mass of teenager = 72 kg

Force F_{foot}=11\ N

Mass of skateboard = 2.8 kg

Suppose, the determine the numerical value for the magnitude of the acceleration of skateboard

We need to calculate the acceleration of skateboard

Using balance equation

F-(m_{1}+m_{2})g=(m_{1}+m_{2})a

Put the value into the formula

11-(72+2.8)\times9.8=(72+2.8)\times a

a=\dfrac{11-(72+2.8)\times9.8}{(72+2.8)}

a=-9.65\ m/s^2

Hence, The acceleration of the skateboard is -9.65 m/s².

5 0
3 years ago
A jogger runs 5.0 km on a straight trail at an angle of 60 south of west. What is the southern component of the run rounded to t
svet-max [94.6K]
The components are the sides S and W of a right triangle with SW = 5 km as the hypotenuse. It helps to sketch out these types problems.

Using the 60°south of west angle would make W adjacent and S opposite to the angle. using SOH CAH TOA

sin(60) = S/5
5*sin(60) = S
5*√(3)/2 = S
4.3 km = S


7 0
4 years ago
HELP PLS! :/
zlopas [31]

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck

7 0
3 years ago
The general direction in which a graph is moving is called a(n)
Allisa [31]

Answer:

i think correct

Explanation:

6 0
2 years ago
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