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Nuetrik [128]
3 years ago
9

What is question 10—20 PTS!!

Physics
1 answer:
Galina-37 [17]3 years ago
8 0
If my math is correct your answer should be 3.0 but correct me if I'm wrong
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Which of the following techniques have been employed to improve the efficiency of fireplaces?
Ksivusya [100]
The first would be the right answer, all catalysts somehow boosts the performance
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4 years ago
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Hii can someone please doo this! 50 pointss.
andrey2020 [161]

Answer:

The periodic table illustrate some of the elements from Hydrogen to Calcium

8 0
3 years ago
A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062
galina1969 [7]

Answer:

Force on the proton will be .73\times 10^{-14}N

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light c=3\times 10^8m/sec

So speed of proton v=\frac{3\times 10^8\times 23}{100}=6.9\times 10^7m/sec

Magnetic field B = 0.00629 T

Charge on proton q=1.6\times 10^{-16}C

Angle between velocity and magnetic field \Theta =137^{\circ}

Force on the proton is equal to F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N

4 0
3 years ago
Select all that apply. Sound is a ____ wave. longitudinal transverse pressure circular
elena-s [515]
The following apply:
Sound is a LONGITUDINAL wave.
Sound is a PRESSURE wave.
Longitudinal waves are waves in which the displacement of the medium is in the same direction as or opposite direction to the direction of wave propagation. An example of longitudinal wave is sound wave. Sound wave is also considered as a pressure wave as the result of the presence of repeating patterns of high and low pressure regions moving through a medium.
5 0
4 years ago
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The electric field between the plates of a parallel-plate capacitor is horizontal, uniform, and has a magnitude E. Asmall object
kirza4 [7]

Answer:

m = 0.041 kg

Explanation:

As we know that the small particle is in equilibrium at an angle of 16 degree with the vertical

so here we can use force balance in vertical and horizontal direction

T cos\theta = mg

T sin\theta = qE

now from above equation we have

T = \sqrt{(mg)^2 + (qE)^2}

also by division of above two equations we have

\frac{qE}{mg} = tan\theta

qE = mg tan\theta

now from above equation again

T = \sqrt{(mg)^2 + (mg)^2 tan^2\theta}

T = mg sec\theta

0.420 = m(9.81) sec 16

m = 0.041 kg

3 0
3 years ago
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