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vodomira [7]
3 years ago
5

A person has a mass of 60 kg. What is the person’s weight in Newtons and in pounds?

Physics
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

137.2 in pounds and in Newton's it's 588.399

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_______ are mountain ranges in the oceans, where the crust is young and there is almost no sediment
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Consider the image above. Vi = the initial velocity and Vf = the final velocity. Is there acceleration? Explain your answer.
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3 years ago
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4-12. The morning inspection of the tank farm finds a leak in the turpentine tank. The leak is repaired. An investigation finds
bonufazy [111]

Answer:

a) V=759.8727\ ft^3

b) \dot V=1.403\times 10^{-3}\ ft^3.s^{-1}

c) t\approx29.541\ s

Explanation:

Given:

  • diameter of hole in the tank, d'=0.1\ in=\frac{1}{120}\ ft
  • position of the hole form the tank bottom, h' =7\ ft
  • initial level of turpentine in the tank before the leakage, h_i=17.3\ ft
  • level of turpentine in the tank after the repair of leakage, h_f=13\ ft
  • diameter of the tank, d=15\ ft
  • density of turpentine oil, \rho=55\ lbm.ft^3

a)

Now, volume of turpentine spilled:

V=A.(h_i-h_f)

where:

A= area of the cross section of the tank's volume

V=\pi .\frac{d^2}{4} \times(h_i-h_f)

V=\pi\times\frac{15^2}{4} \times(17.3-13)

V=759.8727\ ft^3

b)

When the tank was full the liquid level was highest:

so velocity form the height of the hole will be given as:

v=\sqrt{2g.(h_i-h')}

v=\sqrt{2\times 32.12\times (17.3-7) }

v=25.722\ ft.s^{-1}

<u>Now we have the flow rate of the spillage given by:</u>

\dot V=(\pi.\frac{d'^2}{4}) \times v

\dot V=\pi\times \frac{(\frac{1}{120})^2 }{4} \times 25.722

\dot V=1.403\times 10^{-3}\ ft^3.s^{-1}

c)

Total time the leak was active can be calculated as:

t=\frac{V}{\dot V}

t=\frac{759.8727}{25.722}

t\approx29.541\ s

7 0
4 years ago
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