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vodomira [7]
3 years ago
5

A person has a mass of 60 kg. What is the person’s weight in Newtons and in pounds?

Physics
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

137.2 in pounds and in Newton's it's 588.399

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A packing crate rests on a horizontal surface. It is acted on by three horizontal forces: 600 N to the left, 200 N to the right,
egoroff_w [7]

Answer:

The resultant force would (still) be zero.

Explanation:

Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.

In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.

By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.

When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.

However, recall that before the 600-N force is removed, the friction on the crate is 400 N. The normal force on the crate (which is in the vertical direction) did not change. As a result, one can hence be assured that the maximum friction would be at least 400 N. That's sufficient for balancing the 200-N force to the right. Hence, the resultant force on the crate would still be zero, and the crate won't move.

6 0
3 years ago
Which of the following statements is true about static electricity?
natta225 [31]
Static electricity can be an alternating current.
3 0
2 years ago
Read 2 more answers
1. The term that describes where the supply curve intersects the demand curve is known as
nadezda [96]
Equilibrium is the answer
6 0
3 years ago
Plz help I will mark brainiest help send answers
Elden [556K]

Answer:

D

Explanation:

3 0
3 years ago
What centripetal force is needed to keep a 7kg mass moving in a circle of 4 meters radius at 15m/s
liq [111]

Answer:

We conclude that the centripetal force needed to keep a 7kg mass moving in a circle of 4 meters radius at 15m/s is 393.75 N.

Explanation:

Given

  • Mass m = 7 kg
  • Radius r = 4 m
  • Velocity v = 15m/s

To determine

We need to determine the centripetal force needed to keep a 7kg mass moving in a circle of 4 meters radius at 15m/s.

We know a centripetal force acts on a body to keep it moving along a curved path.

We can determine the centripetal force using the formula

F_c=\frac{mv^2}{r}

where

  • m is the mass
  • v is the velocity
  • r is the radius
  • F_c is the centripetal force

substitute m = 7, r = 4, and v = 15 in the formula

F_c=\frac{mv^2}{r}

F_c=\frac{7\left(15\right)^2}{4}

F_c=\frac{1575}{4}

F_c=393.75 N

Therefore, we conclude that the centripetal force needed to keep a 7kg mass moving in a circle of 4 meters radius at 15m/s is 393.75 N.

7 0
3 years ago
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